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help with combining small codes into one big one!

Posted on 2011-03-01
4
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Last Modified: 2012-06-21
i have three scripts i want to merge them together .. and so far i havent been successful!
import bugdisp
import time

 
for i in range(1, 2):
	bugdisp.sendCommand('savetext c:\hi2393993.txt ' )
	time.sleep(100)

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import time
import bugdisp

for i in range(1, 10):
	bugdisp.sendCommand('x A90 1')
	time.sleep(1)

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import os


os.system('wbugdisp.exe')
time.sleep(5)

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Question by:zoomer003
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4 Comments
 
LVL 16

Expert Comment

by:sjklein42
ID: 35009288
I am not a Python expert but this should give you the idea.

You are merging three timer-based loops.  The way to do that is to create a new timer-based loop with the least-common-denominator of the individual timers.  In this case, I made it a one-second loop.  Each time through the loop, each of your actions "checks" to see if it is time for it to execute.  If so, it does.  Then wait a second and check again to see what needs to be done.

import bugdisp
import time
import os

# for 101 seconds, check each second ...

for i in range(0, 100):
	# First time only, start wbugdisp
	if ( i == 0 ): os.system('wbugdisp.exe')

	# First and last time, savetext
	if ( i == 0 ) || ( i == 100 ): bugdisp.sendCommand('savetext c:\hi2393993.txt ' )

	# Every ten seconds, do it
	if ( i < 10 ) == 0: bugdisp.sendCommand('x A90 1')

	# Wait for the next second to tick
	time.sleep(1)

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0
 
LVL 6

Expert Comment

by:LeeeRussell
ID: 35009302
What do you want the merged script to do?  I don't think that's obvious from the question you've asked.
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LVL 16

Accepted Solution

by:
sjklein42 earned 500 total points
ID: 35009374
Sorry, I had a typo in the last test.

import bugdisp
import time
import os

# for 101 seconds, check each second ...

for i in range(0, 100):
	# First time only, start wbugdisp
	if ( i == 0 ): os.system('wbugdisp.exe')

	# First and last time, savetext
	if ( i == 0 ) || ( i == 100 ): bugdisp.sendCommand('savetext c:\hi2393993.txt ' )

	# For the first ten seconds, do this
	if ( i < 10 ): bugdisp.sendCommand('x A90 1')

	# Wait for the next second to tick
	time.sleep(1)

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0
 

Author Closing Comment

by:zoomer003
ID: 35018140
Thank you
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