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SQL: count question

We have 20 sales reps. I am creating a basic query that counts how many items sold this month per sales rep.

SELECT SR.SalesRep, COUNT(*)
FROM SalesReps SR LEFT OUTER JOIN Items I ON I.SalesRep = SR.SalesRepNo
GROUP BY SR.SalesRep

I want all 20 Sales reps to show up, even if they did not sell anything. If they didn't sell anything, I want to see a 0.

However, since ONLY 13 sales reps sold something thus far in March, I am only getting 13 items, not all 20.

How do I modify my query to show all 20 sales reps whether they sold something or not.
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InfoTechEE
Asked:
InfoTechEE
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1 Solution
 
Aneesh RetnakaranDatabase AdministratorCommented:
SELECT SR.SalesRep, ( select COUNT(*) from Items I where I.SalesRep = SR.SalesRepNo )
FROM SalesReps SR
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InfoTechEEAuthor Commented:
Sorry, that did not help.
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Aneesh RetnakaranDatabase AdministratorCommented:
whats the error , can you show me the results
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himanshutCommented:
Oops!! wrong thread
Damn..
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InfoTechEEAuthor Commented:
Sure...I did not want to make it confusing, so I used aliases for my table names...Here is the actual code, and the results.


SELECT R.DisplayName, (DATEDIFF(dd,r.entered,getdate())/365) as Years_as_AE, 
(select COUNT(*) from Jobs J where J.SalesRep = R.RsrcNo and J.Entered >= '3/1/11') as Jobs_Booked
FROM Jobs J LEFT OUTER JOIN Resources R ON R.RsrcNo = J.SalesRep
WHERE R.RsrcNo IN (1743, 4986, 1672, 1821, 4214, 3623, 4089, 4690, 3011, 4872, 1662, 4868, 4068, 4663, 2705, 1093, 3749, 5100)
AND R.[Disabled] = 0
AND J.Entered >= '3/1/11'
GROUP BY R.RsrcNo, R.DisplayName, R.Entered
ORDER BY COUNT(*) desc

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Book1.xlsx
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Aneesh RetnakaranDatabase AdministratorCommented:
SELECT R.DisplayName, (DATEDIFF(dd,r.entered,getdate())/365) as Years_as_AE,
(select COUNT(*) from Jobs J where J.SalesRep = R.RsrcNo and J.Entered >= '3/1/11') as Jobs_Booked
FROM  Resources R
WHERE R.RsrcNo IN (1743, 4986, 1672, 1821, 4214, 3623, 4089, 4690, 3011, 4872, 1662, 4868, 4068, 4663, 2705, 1093, 3749, 5100)
AND R.[Disabled] = 0
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InfoTechEEAuthor Commented:
That worked. Can you explain please? I always thought you needed a group by in order to do a count.
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Aneesh RetnakaranDatabase AdministratorCommented:
this one used a subquery, if you use a subquery you dont really need a Group by clause
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Ephraim WangoyaCommented:
try
SELECT RES.DisplayName, RES.Years_as_AE, RES.Jobs_Booked 
FROM
	(SELECT R.DisplayName, (DATEDIFF(dd,r.entered,getdate())/365) as Years_as_AE, R.Entered, 
		   (select COUNT(*) from Jobs J where J.SalesRep = R.RsrcNo and J.Entered >= '3/1/11') as Jobs_Booked
	FROM Jobs J 
	LEFT OUTER JOIN Resources R ON R.RsrcNo = J.SalesRep
	WHERE R.RsrcNo IN (1743, 4986, 1672, 1821, 4214, 3623, 4089, 4690, 3011, 4872, 1662, 4868, 4068, 4663, 2705, 1093, 3749, 5100)
	AND R.[Disabled] = 0
	AND J.Entered >= '3/1/11') RES
GROUP BY RES.RsrcNo, RES.DisplayName, RES.Entered
ORDER BY COUNT(*) DESC

Open in new window

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SharathData EngineerCommented:
Try like this.
SELECT SR.SalesRep, 
       ISNULL(cnt,0) Cnt 
  FROM SalesReps SR 
       LEFT OUTER JOIN (  SELECT SalesRep, 
                                 COUNT(* ) cnt 
                            FROM Items 
                        GROUP BY SalesRep) I 
         ON I.SalesRep = SR.SalesRepNo

Open in new window

In your code, you can try like this.
SELECT R.DisplayName, 
         (DATEDIFF(dd,r.entered,GETDATE()) / 365) AS Years_as_AE, 
         ISNULL(Cnt,0)                            AS Jobs_Booked 
    FROM Jobs J 
         LEFT OUTER JOIN (  SELECT RsrcNo, 
                                   COUNT(* ) cnt 
                              FROM Resources 
                             WHERE RsrcNo IN (1743,4986,1672,1821, 
                                              4214,3623,4089,4690, 
                                              3011,4872,1662,4868, 
                                              4068,4663,2705,1093, 
                                              3749,5100) 
                                   AND [Disabled] = 0 
                          GROUP BY RsrcNo) R 
           ON R.RsrcNo = J.SalesRep 
   WHERE J.Entered >= '3/1/11' 
ORDER BY Cnt DESC

Open in new window

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