Solved

Access 2003 chaeck field to see if it contains a certain pattern

Posted on 2011-03-02
5
316 Views
Last Modified: 2012-05-11
Hi There,

I have a 12 digit field.
I want to be able to check if anywhere in that string it contains 4 consecutive non numeric characters.

eg

1BLT010001   No
2POLK1000    Yes
POL1000        NO
POLK9999      yes

Any Ideas
0
Comment
Question by:EWHTLC
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
  • 2
5 Comments
 
LVL 120

Assisted Solution

by:Rey Obrero (Capricorn1)
Rey Obrero (Capricorn1) earned 250 total points
ID: 35017059
you will need a function to do that, place this codes in a regular module
is there a possibility to have more than 4 consecutive Alpha characters


function count4Alpha(str) as boolean
count4Alpha=false
if len(str) < 4 then count4Alpha=False: exit function

dim j, strA as string, xCnt as integer
strA="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
for j=1 to len(str)
      if  instr(strA,mid(str,j,1))>0 then
         xCnt=xcnt +1
         if xcnt>=4 then
             count4Alpha=true
             exit function
         end if
         else
         xCnt=0
     end if
next

end function



you can use the function in a query like this

select [field], count4Alpha([field])
fro tableName
0
 
LVL 11

Accepted Solution

by:
LambertHeenan earned 250 total points
ID: 35018166
Here is an alternative function that checks for any desired number of alpha characters in a row...


function strNStringAlpha(strInput, nConsecutive) as string
' Checks it there is any string of nConsecutive Alpha characters
' (A-Z, a-z) and returns the string if found
dim nLen as Long
dim n as Long
dim c as String 
dim strResult as string 
dim nAlpha
	nLen = Len(strInput)
	For n = 1 to nLen
		c = Ucase(mid(strInput,n,1))
		If c >="A" and c <= "Z" then
			nAlpha = nAlpha + 1
			strResult = strResult & mid(strInput,n,1)
			if nAlpha = nConsecutive then
				Exit For
			End If
		Else
			nAlpha = 0
			strResult = ""
		End If
	Next N
	strNStringAlpha = strResult
End Function

Open in new window

0
 

Author Comment

by:EWHTLC
ID: 35019666
Both Solutions worked a treat.
2nd one slightly better in that it looked for 4 consecutives.

Brilliant response.

Thanks you for your time

Will split the points.
0
 

Author Closing Comment

by:EWHTLC
ID: 35019676
thanks
0
 
LVL 11

Expert Comment

by:LambertHeenan
ID: 35019912
My pleasure.
0

Featured Post

Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

In a multiple monitor setup, if you don't want to use AutoCenter to position your popup forms, you have a problem: where will they appear?  Sometimes you may have an additional problem: where the devil did they go?  If you last had a popup form open…
You need to know the location of the Office templates folder, so that when you create new templates, they are saved to that location, and thus are available for selection when creating new documents.  The steps to find the Templates folder path are …
Show developers how to use a criteria form to limit the data that appears on an Access report. It is a common requirement that users can specify the criteria for a report at runtime. The easiest way to accomplish this is using a criteria form that a…
In Microsoft Access, learn how to “cascade” or have the displayed data of one combo control depend upon what’s entered in another. Base the dependent combo on a query for its row source: Add a reference to the first combo on the form as criteria i…

729 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question