Oracle: How to calculate time according to row

Hello Again,
I have a table that holds data regarding the users' activity on the phone. It looks like this

Agent      date      signofftime      status
John      1/4/2011      11:17:33      BREAK                        
John      1/4/2011      11:35:56      Signed ON
John      1/4/2011      13:47:08      LUNCH                        
John      1/4/2011      14:22:43      Signed ON
Jane      1/4/2011      11:18:23      BREAK                        
Jane      1/4/2011      11:34:23      Signed ON
Jane      1/4/2011      12:00:05      LUNCH                        
Jane      1/4/2011      12:30:24      Signed ON

I want to calculate the time difference in hh:mm:ss between break and lunch status and the 'SignOn' time that immediately follows on the next row.

This table holds multiple users and multiple dates. It is certain tho that the Break and Lunch statuses are always followed by Signed on.

thank you in advance!

lemmohr
lemmohrAsked:
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sdstuberConnect With a Mentor Commented:
SELECT *
  FROM (SELECT agent,
               status,
               t,
               TO_CHAR(
                   TRUNC(SYSDATE)
                   + (t - LAG(t) OVER (PARTITION BY agent ORDER BY t)),
                   'hh24:mi:ss'
               )
                   diff
          FROM (SELECT agent,
                       TO_DATE(
                           signoffdate || signofftime,
                           'mm/dd/yyyyhh24:mi:ss'
                       )
                           t,
                       status
                  FROM yourtable))
 WHERE diff IS NOT NULL
ORDER BY agent, t
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lemmohrAuthor Commented:
how do i edit the points here? I put 250 by mistake, should be 500
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sdstuberCommented:
I'm assuming your date strings are  mm/dd/yyyy,  if not, adjust the format accordingly in the to_date call
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awking00Commented:
Given your example, what do you expect the output to look like?
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NewDan526Commented:
Accurate analysis will save a lot of (re)development time and cost.  So its worth commenting on here...

ASSUMPTIONS/COMMENTS:
1. Your table looks like this: (I would consider making date and signofftime one timestamp column - unless you have a specific reason not to)
      CREATE TABLE timeclock
      (
         agent        VARCHAR2(20),
         signofftime  TIMESTAMP,
         status       VARCHAR2(20)
      );

2.  Your objective is to calculate the time your (presumably hard-working) employees are not working.

3. You are not addressing the last time on one day to the first on the next, and there are no night shifts crossing midnight.

4.  Your are NOT calculating how long they work (which would be a useful metric for the business since you should know when they leave for the day)

5. You are NOT covering any variations or exceptions (at this point), everybody always clocks in and out appropriately, and there are no data errors.

-------------
SOLUTION:
SELECT *
  FROM (SELECT agent,
               LAG(status) OVER (PARTITION BY agent ORDER BY SIGNOFFTIME) status,
               (SIGNOFFTIME - LAG(SIGNOFFTIME)
                  OVER (PARTITION BY agent ORDER BY SIGNOFFTIME)) as diff,
               SIGNOFFTIME
          FROM TIMECLOCK
          )
 WHERE diff IS NOT NULL
   and status in('BREAK','LUNCH')
ORDER BY agent, SIGNOFFTIME

--------------
RESULTS:
"AGENT"      "STATUS"      "DIFF"      "SIGNOFFTIME"
"Jane"      "BREAK"      0:16:0.0      04-JAN-11 11.34.23.000000000 AM
"Jane"      "LUNCH"      0:30:19.0      04-JAN-11 12.30.24.000000000 PM
"John"      "BREAK"      0:18:23.0      04-JAN-11 11.35.56.000000000 AM
"John"      "LUNCH"      0:35:35.0      04-JAN-11 02.22.43.000000000 PM
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lemmohrAuthor Commented:
i apologize, I thought i already awarded the points.
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