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unique number from current date

Posted on 2011-03-03
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Last Modified: 2012-05-11
like the following in t-sql
declare @tempdate varchar(23)
set @tempdate = CONVERT(VARCHAR(23), GETDATE(), 121)
select replace(replace(replace(replace(@tempdate,'-',''),' ',''),':',''),'.','')

what would be the feature to get a unique number from date in access?
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Question by:anushahanna
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11 Comments
 
LVL 12

Accepted Solution

by:
Paul_Harris_Fusion earned 500 total points
ID: 35028729
dim f as double
f = CDbl(Now())

This will give you a decimal number corresponding to the current date time.
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LVL 77

Assisted Solution

by:peter57r
peter57r earned 500 total points
ID: 35028781
I guess you can do...
cdbl(Now())*10000000000

I wouldn't like to guarantee uniqueness, although I don't see that your t-sql expression does that either.
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LVL 75
ID: 35029588
Date with Time is already unique.

mx
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LVL 6

Author Comment

by:anushahanna
ID: 35029622
would we do something with date and time in access to produce a unique number? basically we will need the equivalent of
GETDATE()
CONVERT
REPLACE
in access code to make it happen?
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LVL 77

Expert Comment

by:peter57r
ID: 35030067
I was interested in mx's comment.

I think it is very likely that the STORED value in a datetime field is unique in an application.  However, as soon as you do what the poster wants it ceases to be unique because the time 'granularity' is broadened - so that stored time values which differ at the nth decimal place all get rounded to the same second.

And to expand on my previous comment - I don't see that a time value which only goes to milliseconds can be thought of as unique.  Access could probably save 5 records in a millisecond.  I would imagine sql server can do more.
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LVL 6

Author Comment

by:anushahanna
ID: 35030240
Thanks for explaining that Peter.

if i can go to ms in access, that is good enough for this application.

how can you get it to the ms with format command?

    Dim DateValue As String
    DateValue= Format(Now(),"dd/mm/yyyy hh:nn:ss")
0
 
LVL 75
ID: 35030973
I guess it depends on what the usage is, which was not specified.
I suppose you could always append or add the Access Autonumber to it.

mx
0
 
LVL 6

Author Comment

by:anushahanna
ID: 35031127
mx, every csv files that is processed needs a unique number attached, when the data is imported into the table.

how would you attach now() and autonumber together?
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LVL 75

Assisted Solution

by:DatabaseMX (Joe Anderson - Microsoft MVP, Access and Data Platform)
DatabaseMX (Joe Anderson - Microsoft MVP, Access and Data Platform) earned 500 total points
ID: 35031264
I guess the table would have an Auto Number field, and you create a combined field with the Formatted Date/Time EG >>> yyyymmddHHnnss & AutoNumber value .... something like that.  Then, no matter if the date/time stamp was identical as Peter noted, you still end up with a unique value.

mx
0
 
LVL 14

Assisted Solution

by:pteranodon72
pteranodon72 earned 500 total points
ID: 35031480
Now() does not report milliseconds.

However, you can get date/time in milliseconds via API call:
Private Type SYSTEMTIME
wYear As Integer
wMonth As Integer
wDayOfWeek As Integer
wDay As Integer
wHour As Integer
wMinute As Integer
wSecond As Integer
wMilliseconds As Integer
End Type

Private Declare Sub GetSystemTime Lib "kernel32" (lpSystemTime As SYSTEMTIME)

Public Function MSdatetime() As String
Dim tS As SYSTEMTIME
Dim sRet
On Error Resume Next
GetSystemTime tS
sRet = tS.wYear & Format(tS.wMonth, "00") & Format(tS.wDay, "00") _
& Format(tS.wHour, "00") & Format(tS.wMinute, "00") & Format(tS.wSecond, "00") _
 & Format(tS.wMilliseconds, "000")
MSdatetime = sRet
End Function

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By formatting each component values into two places, you'll get different numbers with millisecond granularity. Be careful-- today's processors can do a lot in a millisecond!

HTH,

pT72
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LVL 6

Author Comment

by:anushahanna
ID: 35033594
thanks for the idea.
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