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SQL sorting

This should be easy but I'm losing my mind here. I need to sort a table. As it is the table gives the results like this

Code      Code description   CodeType
6532        NNNNNNN                    6
7853         MMMMMM                    7
653            VVVVVV                   6
785             LLLLLLLL                  7
0253        XXXXXX                        0
1200         Sme irrelevant           1
2250     BBBBBBBBBBB             2
225        XBXBX                           2
120        XXXXXXXXX                  1
025      ABCS                                0

What I need is this
0253    same desc as above          0
025       same -----------------           0
1200      same                                  1
1201      same ----------------            1
1205       same---------------
120       same -------------                 1
2250     same-----------------               2
225       same----------                         2
6532     same--------------                    6
653         same  -----------                    6
and so on. Basically what i need is Code column to be sorted by ASC order but each 3 length record should follow right after similarity ends. More precisely if code is 2250 and afterwards comes 2251, 2253,2254 this should end with 225. Code is nchar(10) field.
Hope I was clear
Thanks
0
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Asked:
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  • 2
1 Solution
 
Ephraim WangoyaCommented:

select Code,      [Code description],   CodeType
from table1
order by case when (Len(Code) > 3) then Left(Code, 3) else Code end,    [Code description],   CodeType
0
 
ThomasianCommented:
select Code
from @t
order by REPLACE(code,' ','z')

Open in new window

OR
select Code
from @t
order by RTRIM(code) + 'z'

Open in new window

0
 
ThomasianCommented:
replace @t with your tablename
0
 
fullstopAuthor Commented:
Thanks, works great
0

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