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Substr Query Question in oracle sql

Posted on 2011-03-04
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Last Modified: 2012-06-27
I have the following select statement with substring

SUBSTR (NVL (historical_separate.work_done, active_separate.work_done),1,INSTR (NVL(historical_separate.work_done, active_separate.work_done),',',1,1)- 1)AS "Repair Code"

say I have data in the field of M21,17,5

The above statement gives me M21

but if I have data of only M21

it gives me blank

I need to have it show M21 not blank.  How do I accomplish this?
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Question by:JDay2
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3 Comments
 
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Accepted Solution

by:
sdstuber earned 500 total points
ID: 35037785
if using 10g try...


regexp_substr(NVL (historical_separate.work_done, active_separate.work_done),'[^,]+')
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LVL 74

Expert Comment

by:sdstuber
ID: 35037808
if you are using an older version that doesn't support  regular expressions try


CASE
           WHEN INSTR(NVL(historical_separate.work_done, active_separate.work_done), ',') > 0
           THEN
               SUBSTR(
                   NVL(historical_separate.work_done, active_separate.work_done),
                   1,
                   INSTR(NVL(historical_separate.work_done, active_separate.work_done), ',', 1, 1)
                   - 1)
           ELSE
               NVL(historical_separate.work_done, active_separate.work_done)
       END
0
 

Author Closing Comment

by:JDay2
ID: 35037847
Thank you for the quick response
0

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