troubleshooting Question

formating of String results.

Avatar of MadIce
MadIce asked on
Microsoft SQL Server
6 Comments2 Solutions333 ViewsLast Modified:
I have the following Code (see below). It works fine except after the first quote a return is inserted.  What I want to do is take this string and use it as part of a where clause but I need the proper format.  Below is the current results.
DLID = '94045' DLID = '
16070' DLID = '
17136' DLID = '
27793' DLID = '
45871' DLID = '
76162' DLID = '
65493' DLID = '
17881' DLID = '
85790' DLSID = '
110509' DLID = '
84701'

This is what I want:

DLID = '94045' DLID = '16070' DLID = '17136' DLID = '27793' DLID = '45871' DLID = '76162' DLID = '65493' DLID = '17881' DLID = '85790' DLID = '110509' DLID = '84701'

Hope this make sense.
declare @LTable table  (
		LTableID int Identity(1,1) Primary key not null,
		LNum varchar(25))


   DECLARE @position int, @string NVARCHAR(MAX),@separator NCHAR(1), @Value varchar(max);
Declare @Cnt int, @MaxCnt int, @BuildWhere varchar(max);
	set @string = '94045
16070
17136
27793
45871
76162
65493
17881
85790
110509
84701'
   SET @position = 1
	set @separator = CHAR(13)
	set @Cnt = 1
   SET @string = @string + @separator
   WHILE charindex(@separator,@string,@position) <> 0
      BEGIN
set @Value = substring(@string, @position, charindex(@separator,@string,@position) - @position)
         INSERT into @LTable
         SELECT @Value
         SET @position = charindex(@separator,@string,@position) + 1

if @Cnt = 1 
set @BuildWhere = ' DLID = ' + '''' + @Value + ''''
else
set @BuildWhere = @BuildWhere + ' DLID = ' + '''' + @Value + ''''

set @Cnt = 2

END

Print @BuildWhere
ASKER CERTIFIED SOLUTION
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