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LINQ to SQL add ScaffoldColumn attribute

Posted on 2011-03-06
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Last Modified: 2012-08-13
Hello,

I am using LINQ to SQL and lets say I have a table called Files.  And in that table, there is a FileID.  I was to give the FileID the attribute of [ScaffoldColumn(false)].

But, my question is, how do I give the FileID that attribute without modifying the linq to sql class file?

I dont want to have to add that attribute everytime i regenerate or make changes to my tables.
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Question by:michael1174
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Expert Comment

by:käµfm³d 👽
ID: 35048084
Partial classes, my friend...  partial classes:
public partial class YouLinq2SqlClass
{
   // Auto generated code
}


[ScaffoldColumn(false)]
public partial class YouLinq2SqlClass
{

}

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Expert Comment

by:käµfm³d 👽
ID: 35048088
I guess it should be more like:
public partial class YouLinq2SqlClass
{
   // Auto generated code

...

    public int FieldId { get;set; }
}


public partial class YouLinq2SqlClass
{
    [ScaffoldColumn(false)]
    public int FieldId { get;set; }
}

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Author Comment

by:michael1174
ID: 35048112
kaufmed,

Thanks for your input.

would my data context be my class?

 AMCDataContext?

Where exactly do I put the partial class?  Do I create a seperate clas file?

Also did you mean:

[ScaffoldColumn(false)]
public int FileID
}
}
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Author Comment

by:michael1174
ID: 35055270
When I'm on my dbml file, i press F7, it creates a seperate class file:

namespace AMC
{
    partial class AMCDataContext
    {
    }
}

but then when i try to recompile, get a lot of errors....

so i'm just unsure how where to put the partial class....



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Accepted Solution

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käµfm³d   👽 earned 2000 total points
ID: 35069153
>>  would my data context be my class?

Whichever class is the class that will have the attribute added to it.

>>  Where exactly do I put the partial class?  Do I create a seperate clas file?

You can if you like; you don't have to. Best practice would have you put in a separate file though, I believe. The name of the file is irrelevant as long as you make the class name the same as the class you are targeting. NOTE both instances of "class" must be marked partial, so if you can't control the definition of the class itself (the original definition), then creating a partial-class add-on will not work.

    http://msdn.microsoft.com/en-us/library/wa80x488(v=vs.80).aspx
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Author Closing Comment

by:michael1174
ID: 35069399
Thank you very much for the answer & explaination.
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Expert Comment

by:käµfm³d 👽
ID: 35071332
NP. Glad to help  = )
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