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Badwords filter, finding only "whole word"
Posted on 2011-03-07
I have the following that works fine
But it finds also false badword within a longer word
Example:
I need to remove "cha"
it will rem it out of" any words cha and more"
but also in this form
"experts exchange" where if finds cha, which is indeed not OK
But it finds also false badword within a longer word
Example:
I need to remove "cha"
it will rem it out of" any words cha and more"
but also in this form
"experts exchange" where if finds cha, which is indeed not OK
function unallowed($reply) {
include($_SERVER['DOCUMENT_ROOT']."/badwords/bw.php");
$star = "*";
for ($i = 0; $i < sizeof($badwords); $i++) {
$censored = substr($badwords[$i], 0,1);
for ($x = 1; $x < strlen($badwords[$i]); $x++) $censored .= $star;
$reply = str_replace($badwords[$i], $censored, $reply);
}
return $reply;
}
And
bw.php looks like this:
<?php
$badwords =
array (
'zzzzz',
etc.....
[X]
Welcome to Experts Exchange
Add your voice to the tech community where 5M+ people just like you are talking about what matters.
- Help others & share knowledge
- Earn cash & points
- Learn & ask questions
4-
3
8 Comments
Active 2 days ago
Use regex with preg_replace, if you want to censor the words out. Or use preg_match to just get a true/false if the word is in the haystack.
http://php.net/manual/en/function.preg-replace.php
http://php.net/manual/en/function.preg-match.php
http://php.net/manual/en/function.preg-replace.php
http://php.net/manual/en/function.preg-match.php
Active 2 days ago
Like this.
<?php
$string = 'Experts Exchange.';
$pattern = '/cha/';
$replacement = '###';
echo preg_replace($pattern, $replacement, $string);
//Echos Experts Ex###nge
?>
Active 2 days ago
You can also do it as an array
<?php
$string = 'Experts Exchange has a lot of answers for questions.';
$patterns = array();
$patterns[0] = '/answers/';
$patterns[1] = '/for/';
$patterns[2] = '/questions/';
$replacements = array();
$replacements[0] = 'problems';
$replacements[1] = 'to';
$replacements[2] = 'solve';
echo preg_replace($patterns, $replacements, $string);
//Echos Experts Exchange has a lot of problems to solve.
?>
Thanks,
but it does not resolve my quest, the first solution is getting the same result as what I do know.
I am looking for it not to pick up "cha" in exchange but to pick it up in a str like: this is cha a str"
as a whole word only
And the other solution I am not up to adapt it
as I did not find a way to make my array working as the pattern
it looks like:
<?php
$badwords =
array (
'zzzzz',
etc.....
but it does not resolve my quest, the first solution is getting the same result as what I do know.
I am looking for it not to pick up "cha" in exchange but to pick it up in a str like: this is cha a str"
as a whole word only
And the other solution I am not up to adapt it
as I did not find a way to make my array working as the pattern
it looks like:
<?php
$badwords =
array (
'zzzzz',
etc.....
Active 2 days ago
Ah ok, I thought you were saying you wanted it to be replaced in any situation. Try this.
<?php
print cleanWords("Experts Exchange cha.");
function cleanWords($value) {
/* strip naughty words */
$badwords = array ('cha');
for ($i = 0; $i < count($badwords); $i++) {
$wordlist .= str_replace(chr(13),'',$badwords[$i]).'|';
}
$wordlist = substr($wordlist,0,-1);
$value = preg_replace("/\b($wordlist)\b/ie", 'preg_replace("/./","*","\\1")', $value);
return $value;
}
?>
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