asked on
manipulating double arrays sent to function
Check the code, should be self explanitory what I'm trying to do.
The function crashes on line:
thespliced[i_word_num][i_w
Obviously because I haven't allocated memory for it.
How do allocate memory for a double array?
The function crashes on line:
thespliced[i_word_num][i_w
Obviously because I haven't allocated memory for it.
How do allocate memory for a double array?
in the parse function:
char **spliced;
return_val = splice(string,thespliced);
int splice(char *string, char *thespliced[])
{
int i_string=0;
int i_word_num=0;
int i_word=0;
int i=0;
for( ; i_string < (strlen(string) - 1) ; ++i_string)
{
if(string[i_string] == ' ')
{
++i_word_num;
i_word = 0;
continue;
}
thespliced[i_word_num][i_word] = string[i_string];
++i_word;
}
return i_word;
}
C
Last Comment
phoffric
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By dynamic do you mean, the array expands as you keep putting more items in it, or just that you can set the dimensions at runtime?
The first option doesn't exist in C. If you want something that expands you have to do it yourself by allocating a bigger array, copying over the data from the original smaller array into the new bigger array and then delete the original array.
The second option, you can do in 2 ways. Do you know the size of one of the dimensions? If so, you can do
char spliced[20][] = malloc(20 * xDim * sizeof(char));
then you get an array with one fixed dimension and one dimension set at runtime.
If you want both dimensions to be able to be set at runtime, then you have to change a bit more code. You can no longer use the array as thespliced[3][6], because the actual address that that refers to is calculated at compile time and if you don't know one of the dimensions, the compiler can't work it out.
To do this, you have to declare your array as
char spliced[] = malloc(xDim * yDim * sizeof(char));
and then pass it to your splice method as
int splice(char *string, char thespliced[], int xDim)
and then you access the array like...
thespliced[i * xDim + j]; // where i and j are the indexes into the array, and xDim is the size of the first dimension
Hope that helps
The first option doesn't exist in C. If you want something that expands you have to do it yourself by allocating a bigger array, copying over the data from the original smaller array into the new bigger array and then delete the original array.
The second option, you can do in 2 ways. Do you know the size of one of the dimensions? If so, you can do
char spliced[20][] = malloc(20 * xDim * sizeof(char));
then you get an array with one fixed dimension and one dimension set at runtime.
If you want both dimensions to be able to be set at runtime, then you have to change a bit more code. You can no longer use the array as thespliced[3][6], because the actual address that that refers to is calculated at compile time and if you don't know one of the dimensions, the compiler can't work it out.
To do this, you have to declare your array as
char spliced[] = malloc(xDim * yDim * sizeof(char));
and then pass it to your splice method as
int splice(char *string, char thespliced[], int xDim)
and then you access the array like...
thespliced[i * xDim + j]; // where i and j are the indexes into the array, and xDim is the size of the first dimension
Hope that helps
Please post your parse and main functions.
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dynamic.