Solved

Making an insert query more efficient

Posted on 2011-03-08
5
270 Views
Last Modified: 2012-05-11
I have written TSQL code in insert two records from one database to another. There are 5 different records to insert into the same table and I find am having to supplier the Join section each time...is there a better way to trim the following code sample so that the join information is only used once preceeding each insert and select statement?
--First insert
INSERT [Testing].dbo.[IFC]

        ( [Field1],

          [Field2],

          [Field3],

          [Field4],

          [Field5]

        )
     

SELECT

      @SupplierInvoiceID,

      'Standing Charge',

      2,

      ROUND ([Standing_Charge],2),

      1

 
FROM MTest.dbo.Data D

INNER JOIN Points  AS P ON

            D.Point_Id = P.Id

INNER JOIN Testing.dbo.Meter M  ON

            P.M1_Code1 = M.MeterNumber COLLATE LATIN1_GENERAL_CI_AI

WHERE [SomeNumber] IS NOT NULL AND Code1 IS NOT NULL
and Date >= '2009-01-01'
 

--second insert
INSERT [Testing].dbo.[IFC]

        ( [Field1],

          [Field2],

          [Field3],

          [Field4],

          [Field5]

        )

SELECT

      @SupplierInvoiceID,

      'Other Charge',

      2,

      ROUND ([Other_Charge],2),

      1

     

FROM MTest.dbo.Data D

INNER JOIN Points  AS P ON

            D.Point_Id = P.Id

INNER JOIN Testing.dbo.Meter M  ON

            P.M1_Code1 = M.MeterNumber COLLATE LATIN1_GENERAL_CI_AI

WHERE [SomeNumber] IS NOT NULL AND Code1 IS NOT NULL
and Date >= '2009-01-01'
0
Comment
Question by:mbs2000
5 Comments
 
LVL 1

Expert Comment

by:TheAnvilGroup
ID: 35069388
Use a CASE statement in the SELECT.

CASE WHEN [YourCondition] = 1 THEN 'Standing Charge'
WHEN [YourCondition] = 2 THEN 'Other Charge'
ELSE 'Not Known'
END

Do this for the Field2 and Field4. The INSERT statement and JOINS will be the same.
0
 
LVL 15

Expert Comment

by:derekkromm
ID: 35069406
INSERT [Testing].dbo.[IFC]

        ( [Field1],

          [Field2],

          [Field3],

          [Field4],

          [Field5]

        )
     

SELECT

      @SupplierInvoiceID,

      F2.F2,

      2,

case when F2.F2 = 'Standing Charge' then ROUND ([Standing_Charge],2) else ROUND([Other_Charge],2) end,

      1

 
FROM (select 'Standing Charge' F2 union select 'Other Charge' F2) f2
cross join (MTest.dbo.Data D

INNER JOIN Points  AS P ON

            D.Point_Id = P.Id

INNER JOIN Testing.dbo.Meter M  ON

            P.M1_Code1 = M.MeterNumber COLLATE LATIN1_GENERAL_CI_AI

WHERE [SomeNumber] IS NOT NULL AND Code1 IS NOT NULL
and Date >= '2009-01-01')
0
 
LVL 32

Expert Comment

by:ewangoya
ID: 35069418
declare @standing_charge float
declare @other_charge float

SELECT
      @standing_charge = ROUND ([Standing_Charge],2),
      @other_charge =  ROUND ([Other_Charge],2)
FROM MTest.dbo.Data D
INNER JOIN Points  AS P ON D.Point_Id = P.Id
INNER JOIN Testing.dbo.Meter M  ON P.M1_Code1 = M.MeterNumber COLLATE LATIN1_GENERAL_CI_AI
WHERE [SomeNumber] IS NOT NULL AND Code1 IS NOT NULL
and Date >= '2009-01-01'

INSERT [Testing].dbo.[IFC]
        ( [Field1],
          [Field2],
          [Field3],
          [Field4],
          [Field5]
        )
     

SELECT @SupplierInvoiceID, 'Standing Charge', 2, @standing_charge, 1
union all
SELECT @SupplierInvoiceID, 'Standing Charge', 2, @other_charge, 1
0
 
LVL 5

Accepted Solution

by:
idmedellin earned 500 total points
ID: 35069734
This is another way
SELECT Round ([Standing_Charge], 2) AS Standing_Charge, Round ([Other_Charge], 2) AS Other_Charge
INTO   #Charge
FROM   mtest.dbo.data d       INNER JOIN points AS p         ON d.point_id = p.id
       INNER JOIN testing.dbo.meter m         ON p.m1_code1 = m.meternumber COLLATE latin1_general_ci_ai
WHERE  [SomeNumber] IS NOT NULL       AND code1 IS NOT NULL       AND DATE >= '2009-01-01'  

INSERT [Testing].dbo.[IFC]       ([Field1],        [Field2],        [Field3],        [Field4],        [Field5])
SELECT @SupplierInvoiceID,       'Other Charge',       2,       Other_Charge,       1
FROM   #Charge

INSERT [Testing].dbo.[IFC]       ([Field1],        [Field2],        [Field3],        [Field4],        [Field5])
SELECT @SupplierInvoiceID,       'Standing Charge',       2,       Standing_Charge,       1
FROM   #Charge

DROP TABLE #Charge

Open in new window

0
 

Author Closing Comment

by:mbs2000
ID: 35073172
Spot on ... exactly what I was after....thanks very much
0

Featured Post

Ransomware-A Revenue Bonanza for Service Providers

Ransomware – malware that gets on your customers’ computers, encrypts their data, and extorts a hefty ransom for the decryption keys – is a surging new threat.  The purpose of this eBook is to educate the reader about ransomware attacks.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
Stored Procedure error 45 47
Upgrading SQL 2005 Express to 2008 R2 Express 31 68
SQL query to summarize items per month 5 53
Restrict result set 1 34
Introduction: When running hybrid database environments, you often need to query some data from a remote db of any type, while being connected to your MS SQL Server database. Problems start when you try to combine that with some "user input" pass…
In SQL Server, when rows are selected from a table, does it retrieve data in the order in which it is inserted?  Many believe this is the case. Let us try to examine for ourselves with an example. To get started, use the following script, wh…
Migrating to Microsoft Office 365 is becoming increasingly popular for organizations both large and small. If you have made the leap to Microsoft’s cloud platform, you know that you will need to create a corporate email signature for your Office 365…
Learn how to create flexible layouts using relative units in CSS.  New relative units added in CSS3 include vw(viewports width), vh(viewports height), vmin(minimum of viewports height and width), and vmax (maximum of viewports height and width).

920 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

14 Experts available now in Live!

Get 1:1 Help Now