pre & post operands in javascript
Greetings,
I want to make sure I understand the different results between the three code examples included of pre & post increment operands.
Example A:
i = 1;
j = ++i;
Example B:
i = 1;
j = i++;
Example A sets both i and j to 2 whereas example B sets i to 2 and j to 1.
I want to make sure why j equals 1 in example B: I believe it is because the increment operand is post which means this code:
j = i++;
Is read like this:
j equals i which equals 1 (j = i)
Increment i so it equals 2 (i++)
Am I correct in my reading of the code from example B? If I am correct, then I would like to apply this logic to the following code:
Example C:
var i = 1;
var j = ++i; // pre-increment: j equals 2; i equals 2
var k = i++; // post-increment: k equals 2; i equals 3
Based on the code above, does k equal 2 because i was previously incremented in var j above it and the new value of i (2) is carried over to the code: var k = i++?
I want to make sure I understand the different results between the three code examples included of pre & post increment operands.
Example A:
i = 1;
j = ++i;
Example B:
i = 1;
j = i++;
Example A sets both i and j to 2 whereas example B sets i to 2 and j to 1.
I want to make sure why j equals 1 in example B: I believe it is because the increment operand is post which means this code:
j = i++;
Is read like this:
j equals i which equals 1 (j = i)
Increment i so it equals 2 (i++)
Am I correct in my reading of the code from example B? If I am correct, then I would like to apply this logic to the following code:
Example C:
var i = 1;
var j = ++i; // pre-increment: j equals 2; i equals 2
var k = i++; // post-increment: k equals 2; i equals 3
Based on the code above, does k equal 2 because i was previously incremented in var j above it and the new value of i (2) is carried over to the code: var k = i++?
Asked:
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