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javascript, select one dropdown changes the selected value of another drop downlist

Posted on 2011-03-08
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Last Modified: 2012-05-11
I have two drop down lists.  Selecting one dropdown changes the selected value of another drop downlist.  If "default" is chosen on list1, then select "All" on list 2.  Also disable selection on list2.  If possible, use onclick.

<select name=list1>
  <option value="default">default</option>
  <option value="choice">choice</option>
</select>

<select name=list2>
  <option value="All">All</option>
  <option value="choice1">choice1</option>
  <option value="choice1">choice2</option>
</select>
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Question by:rgbcof
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3 Comments
 
LVL 82

Accepted Solution

by:
leakim971 earned 250 total points
ID: 35075868
Check this :


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script language="javascript">

	window.onload = function() {
		//var list1 = document.getElementById("list1");
		var list1 = document.getElementsByName("list1")[0];
		updateList2(list1.options[list1.selectedIndex].value);
	}

	function updateList2(val) {
		//list2 = document.getElementById("list2");
		var list2 = document.getElementsByName("list2")[0];
		if(val == "default") {
			list2.selectedIndex = 0
			for(var i=1;i<list2.options.length;i++) {
				list2.options[i].disabled = true;
			}
		}
		else {
			for(var i=1;i<list2.options.length;i++) {
				list2.options[i].disabled = false;
			}
		}
	}
</script>
</head>
<body>
<select name="list1" onchange="updateList2(this.value);" >
  <option value="default">default</option> 
  <option value="choice">choice</option>
</select>
<select name="list2">
  <option value="All">All</option> 
  <option value="choice1">choice1</option>
  <option value="choice1">choice2</option>
</select>
</body>
</html>

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Author Closing Comment

by:rgbcof
ID: 35080227
leakim971 you are awesome in providing so much detail and actual code.  Thank you.
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LVL 82

Expert Comment

by:leakim971
ID: 35082096
You're welcome! Thanks for the points! Have a nice day!
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