Solved

DataGrid Template Column

Posted on 2011-03-09
5
494 Views
Last Modified: 2013-12-17
Hi,

I have a DataGrid with a TemplateColumn which contains a textbox. I want to be able to bring back the value of the textbox to a string. Can anyone help me do this?

Thanks
0
Comment
Question by:Gaz124
  • 3
  • 2
5 Comments
 

Author Comment

by:Gaz124
ID: 35082002

I have tried the following code with little success!
protected void Button1_Click(object sender, EventArgs e)
        {
            //Get Username
        string[] username = Request.ServerVariables["LOGON_USER"].ToString().Split('\\');
            globalfunctions getAttribute = new globalfunctions();

            string storeEmail = getAttribute.getADattribute(username[1], "mail");

            DataGridItem item = (sender as Button).NamingContainer as DataGridItem;
            string Name = ((TextBox)(item["QTY"].FindControl("TextBox2"))).Text;

            TextBox Qty = (TextBox)((Button)sender).NamingContainer.FindControl("TextBox2");

Open in new window

0
 
LVL 96

Expert Comment

by:Bob Learned
ID: 35090455
It looks like you are trying to use FindControl with the item, but I don't believe that you have the right reference, but it is difficult to be sure, without seeing the HTML declaration for the DataGrid.
0
 

Author Comment

by:Gaz124
ID: 35093274
Ok, heres the code asp and c#. I can get every other part of the datagrid to my .csv but not the template column, Frustrating!!


<asp:GridView ID="GridView1" runat="server" DataSourceID="as400" 
        AutoGenerateColumns="False" CellPadding="4" ForeColor="#333333" 
        GridLines="None">
        <RowStyle BackColor="#FFFBD6" ForeColor="#333333" />
        <Columns>
         <asp:BoundField DataField="IMSKU" HeaderText="SKU"  />
         <asp:BoundField DataField="IMDESC" HeaderText="Description"  />
         <asp:BoundField DataField="JFFXQT" HeaderText="Required" 
                ItemStyle-HorizontalAlign="Center" >
<ItemStyle HorizontalAlign="Center"></ItemStyle>
            </asp:BoundField>
            <asp:TemplateField HeaderText="Qty"> 
                <ItemTemplate>
                    <asp:TextBox ID="TextBox2" runat="server"></asp:TextBox>
                </ItemTemplate>
            </asp:TemplateField>
           
        </Columns>
        <FooterStyle BackColor="#990000" Font-Bold="True" ForeColor="White" />
        <PagerStyle BackColor="#FFCC66" ForeColor="#333333" HorizontalAlign="Center" />
        <SelectedRowStyle BackColor="#FFCC66" Font-Bold="True" ForeColor="Navy" />
        <HeaderStyle BackColor="#990000" Font-Bold="True" ForeColor="White" />
        <AlternatingRowStyle BackColor="White" />
    </asp:GridView>


protected void Button1_Click(object sender, EventArgs e)
        {

            //Get Username
        string[] username = Request.ServerVariables["LOGON_USER"].ToString().Split('\\');
            globalfunctions getAttribute = new globalfunctions();

            string storeEmail = getAttribute.getADattribute(username[1], "mail");

            //append to csv file
            StreamWriter sw = File.AppendText("e:\\results\\decdiylayout.csv");

            //seperate datagrid to comma seperated values
             for (int i = 0; i < GridView1.Rows.Count; i++)
        {
            string strRowVal = "";
            for (int j = 0; j < GridView1.Rows[i].Cells.Count; j++)
            {
                if (strRowVal == "")
                {
                    strRowVal = DateTime.Now + "," + username[1].Remove(3)+ "," + Layout.Text + "," + GridView1.Rows[i].Cells[j].Text;
                }
                else
                {
                    strRowVal =  strRowVal + "," + GridView1.Rows[i].Cells[j].Text;
                }
            }
            sw.WriteLine(strRowVal);
        }
        sw.Close();

Open in new window

0
 
LVL 96

Accepted Solution

by:
Bob Learned earned 500 total points
ID: 35099839
DataGrid:  1.1
GridView:  >=2.0

You need to call FindControl on the GridViewRow, as in this example:

GridViewRow row = this.GridView1.Rows[0];
TextBox textBox = (TextBox)row.FindControl("TextBox1");

Open in new window

0
 

Author Comment

by:Gaz124
ID: 35107937
WOW TheLearnedOne Thats Great!!
0

Featured Post

Industry Leaders: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

This article is for Object-Oriented Programming (OOP) beginners. An Interface contains declarations of events, indexers, methods and/or properties. Any class which implements the Interface should provide the concrete implementation for each Inter…
This article aims to explain the working of CircularLogArchiver. This tool was designed to solve the buildup of log file in cases where systems do not support circular logging or where circular logging is not enabled
Although Jacob Bernoulli (1654-1705) has been credited as the creator of "Binomial Distribution Table", Gottfried Leibniz (1646-1716) did his dissertation on the subject in 1666; Leibniz you may recall is the co-inventor of "Calculus" and beat Isaac…
The Email Laundry PDF encryption service allows companies to send confidential encrypted  emails to anybody. The PDF document can also contain attachments that are embedded in the encrypted PDF. The password is randomly generated by The Email Laundr…

730 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question