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As it stands you cannot reverse them, you have to do some groundwork first.
That is, given R, to find X you must first replace 'Y' with what it corresponds to for X
Simple example:
R = 2X + 3Y
=> Y = (R-2X) / 3
Hence:
R = 2X + (R-2X) / 3
Once you reach that state, since you know the value of R and you want to find X, you then go about making X the subject of the equation
Continuing from the example above:
R = 2X + (R-2X) / 3
=> 3R = 6X + (R-2X)
=> 2R = 4X
=> X = R / 2
You do the SAME process for Y.
Thus given 'R' (range) you can find X and Y
You repeat the same steps for H (heading).