Need unique count of customer name to reseller name formula ASAP!!!

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

glabossi

ASKER

This almost worked. But it is still not giving it. I have some of them that are 1, but the rest are more than one. The example below should show a unique count of 1 for this reseller and it shows two.

Reseller Customer Unique Count
INSIGHT 1252 Properties, Inc. 2
INSIGHT 1252 Properties, Inc. 2

You didn't mentioned that you had duplicate on your data... let me see now.

Hello glabossi,

If you have a reseller name in D3 then you can use this formula for a count of different customers, see attached.

=SUMPRODUCT((MATCH(A$2:A$8&"-"&B$2:B$8,A$2:A$8&"-"&B$2:B$8,0)=ROW(A$2:A$8)-ROW(A$2)+1)*(A$2:A$8=D3))

regards, barry

Here's the attachment......

barry
26874647.xlsx

It's not that simple Barry...he wants unique costumers that are only from that reseller! That's the problem...

In jppinto's sample workbook, you can use the formula for the count of unique customers of a reseller:
=SUMPRODUCT((A$2:A$90=F4)/((A$2:A$90<>F4)+COUNTIFS(A$2:A$90,F4,B$2:B$90,B$2:B$90)))

The reference to row 90 is arbitrary, and may extend beyond the data. The reference to cell F4 is to the reseller's name.

Barry's formula works as requested (and tolerates blank cells to boot)--but mine is shorter for a change.

Here are both formulas in Barry's sample workbook:
26874647.xlsx

I'm I the only one that understood the question or the only one that didn't?!?

It's my understanding that the user wants unique customers of a reseller that are not customers of other resellers, right?

jppinto

darcy_morse

use a countif on the customer for the same column. That will give the number of customers in that column. Then filter on the count field, and filter for the quantity of 1. This will display the reseller and unique customer.

@darcy_morse: The problem is when there are duplicate resellers+customers! If there wheren't duplicates, my fisrt solution would work!

glabossi

ASKER

jppinto is correct. My original posts did not include duplicates but the formula needs to account for it.

darcy_morse

col A Col B col C Col D
Reseller Customer = concatenate(A1,"-",B1) =countif(B:B,B1) - countif(C:C,C1)

Column D searches for number of customers and sutracts number of reseller customer combinations. From there you can look where column D = 0.

To get the counts of 2 and 1, you might use:
=SUMPRODUCT((A$2:A$90=D3)*(COUNTIF(B$2:B$90,B$2:B$90)=1))
26874647.xlsx

Sorry glabossi, I misunderstood the requirement, sounds like you understood it better jp!

Here's a formula solution

=SUM(IF(FREQUENCY(IF(COUNTIFS(A$2:A$10,"<>"&D2,B$2:B$10,B$2:B$10)=0,IF(B$2:B$10<>"",MATCH(B$2:B$10,B$2:B$10,0))),ROW(B$2:B$10)-ROW(B$2)+1),1))

That's an array formula that needs to be confirmed with CTRL+SHIFT+ENTER

where D2 contains the reseller name

see attached example

regards, barry
26874647v2.xlsx

If there might be duplicates, then you get 2 and 1 with:
=SUMPRODUCT((COUNTIF(B$2:B$9,B$2:B$9)=COUNTIFS(A$2:A$9,D3,B$2:B$9,B$2:B$9))/((COUNTIF(B$2:B$9,B$2:B$9)<>COUNTIFS(A$2:A$9,D3,B$2:B$9,B$2:B$9))+COUNTIFS(A$2:A$9,D3,B$2:B$9,B$2:B$9)))
26874647.xlsx

just to clarify, then - I think the last formula suggested by Brad will give the same results as the last formula that I suggested - my version also allows blank rows......

regards, barry

SOLUTION

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

ASKER CERTIFIED SOLUTION