How to deletw Rows with duplicate data element?

Hello,

How do I delete rows with duplicate Child in my xml file? For example if my xml file contains

<Row>
<Item>1</Item>
<Child>1</Child>1
</Row>
<Row>
<Item>2</Item>
<Child>1</Child>1
</Row>
<Row>
<Item>3</Item>
<Child>2</Child>1
</Row>
<Row>
<Item>4</Item>
<Child>1</Child>1
</Row>

I would like to create a new xml file with the following data (removing Rows with duplicate Child)

<Row>
<Item>1</Item>
<Child>1</Child>1
</Row>
<Row>
<Item>3</Item>
<Child>2</Child>1
</Row>

I am uding VB.NET (VS2010)
Thanks,

Victor

vcharlesAsked: 2011-03-10

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LVL 60

Geert BormansInformation ArchitectCommented: 2011-03-10

There are a zillion articles out there that explain how to run an XSLT in VB.Net

I list a few here that seem correct to me
Note that you need to save the XSLT as a sepêrate file and I assume that you might allready have the XML as an object

http://www.vbdotnetheaven.com/UploadFile/Globalking/xmlxslt108112006012217AM/xmlxslt1.aspx
http://stackoverflow.com/questions/1187782/vb-net-apply-xsl-transformation-to-xml-file

LVL 60

Geert BormansInformation ArchitectCommented: 2011-03-10

You could use a simple XSLT

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   version="1.0">
<xsl:key name="row" match="Row" use="Child"/>
    <xsl:template match="node()">
        <xsl:copy>
            <xsl:copy-of select="@*"/>
            <xsl:apply-templates select="node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="Row[generate-id() = generate-id(key('row', Child)[1])]">
        <xsl:copy-of select="."/>
    </xsl:template>
    <xsl:template match="Row[not(generate-id() = generate-id(key('row', Child)[1]))]"/>
</xsl:stylesheet>

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vcharlesAuthor Commented: 2011-03-10

Sorry,

I'm lost, how do i incoporate this code in VB.NET? What do i need to import in my project to use this code? How do you create the new xml file without duplicate?

Thanks,

Victor