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Query Replace Help

Posted on 2011-03-10
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Last Modified: 2012-05-11
I'm trying to do a replace on a filed that has many different options.

filedname = post, table = posts

[url=http://domain.com/blah.flv]blah video[/url]
[url=http://domain.com/video/name.mp4]name of him[/url]
[url=http://domain.com/video/2001/funny.flv]funny clip[/url]

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I want to update these to make them look like:

[media]http://domain.com/blah.flv[/media]
[media]http://domain.com/video/name.mp4[/media]
[media]http://domain.com/video/2001/funny.flv[/media]

Open in new window

0
Comment
Question by:N R
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7 Comments
 
LVL 32

Expert Comment

by:Ephraim Wangoya
ID: 35097401
update table
set fieldname = REPLACE(fieldname, '')

update table
set fieldname =REPLACE(fieldname, '
', '[/media]')
0
 
LVL 11

Author Comment

by:N R
ID: 35097418
can you put all that in code tags so I can see it,  the url tags disappeared haha.
0
 
LVL 32

Expert Comment

by:Ephraim Wangoya
ID: 35097426
Here
update table
set fieldname = REPLACE(fieldname, '')

update table
set fieldname =REPLACE(fieldname, '', '[/media]')

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0
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Besides backup, any IT division should have a disaster recovery plan. You will find a few tips below relating to the development of such a plan and to what issues one should pay special attention in the course of backup planning.

 
LVL 32

Expert Comment

by:Ephraim Wangoya
ID: 35097430
Not that, let me redo
0
 
LVL 32

Expert Comment

by:Ephraim Wangoya
ID: 35097446
Here is the correct one
update table
set fieldname = REPLACE(fieldname, '[url=', '[media]')

update table
set fieldname =REPLACE(fieldname, '[/url]', '[/media]')

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0
 
LVL 11

Author Comment

by:N R
ID: 35097469
Well, that still doesn't get me there that will make the result set be:
[media]http://domain.com/blah.flv]blah video[/media]
[media]http://domain.com/video/name.mp4]name of him[/media]
[media]http://domain.com/video/2001/funny.flv]funny clip[/media]

Open in new window


but what I need is:
[media]http://domain.com/blah.flv[/media]
[media]http://domain.com/video/name.mp4[/media]
[media]http://domain.com/video/2001/funny.flv[/media]

Open in new window

0
 
LVL 75

Accepted Solution

by:
käµfm³d   👽 earned 500 total points
ID: 35097472
How about this?
update posts set post = '[media]' + SUBSTRING(post, charindex('=', post) + 1, charindex(']', post, 2) - charindex('=', post) - 1) + '[/media]'

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0

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