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Change the productID of my entire Product table according to clients changing ranking

Posted on 2011-03-10
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Last Modified: 2012-05-11
My web app presents an entire category of products displayed using (ORDER BY Product.ProductID).  My client wants to choose which products are side by side and/or at the top of the page. To add a Rank column to my product table would force the client to manually assign an integer to each product in his catalog. I am thinking there is a way to change the ProductID to accommodate him instead. Some way of reordering the table.  If anyone can help by either suggesting code or just tell me I am wasting my time, please do.
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Question by:pathfinder8008
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Accepted Solution

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quizwedge earned 500 total points
ID: 35098047
There's probably a better solution. If the product ID is only used in the one table, then this might be doable without it being a major pain. If you have to update orders, etc. you're running the risk of corrupting data or, at best, having a lot of data to update. The other problem comes in when you add in more products. If you already have product 1, 2, and 3 and the customer wants to put 4 in between 1 and 2 you'll have to renumber again.

What about using your Rank idea, but with a modification? By default, rank is Null. In your query, you can do IsNull(Rank, 999999) (or some other large number). Then sort by Rank, ProductID. Anything with Null will show up at the end.
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LVL 52

Expert Comment

by:Carl Tawn
ID: 35098140
you shouldn't mess about with ID. The ID is there to uniquely identify each record, if you want to force an particular order then you would be better with a separate column to accomodate that.
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Author Closing Comment

by:pathfinder8008
ID: 35099381
Thanks quizwedge, I added the Rank column and used (ORDER BY IsNull(Rank, 9999), Product.ProductID) to my SELECT ROW_NUMBER() and it works great. This solution will not over tax my client.  And yes, carl tawn you are absolutely correct about messing with the uniqueID. It was clutching at straws.  Thanks again to the pros at EE.
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