asked on

Too much is printed.

Given the code below
<?php
$dag = $dagen_1a;
//echo "<tr>";
$cols = 0;
$rows = 0;
while ($dag <= $sista_vakt_dagen)
{
$dag2 = ($dag - 75000);
//Print date (first print column)
echo "<tr><td valign=\"top\" height=\"20px\" class=\"vaktvisning\">".date('Y-m-d',$dag)."</td>";
//---------------------------------------
$SQL1 = " SELECT * FROM medlem_vakt_test LEFT JOIN bryggplatser ON medlem_vakt_test.medlemsnr = bryggplatser.medlemsnr WHERE (medlem_vakt_test.dagkod1 between '$dag2' AND '$dag') OR (medlem_vakt_test.dagkod2 between '$dag2' AND '$dag') ORDER BY medlem_vakt_test.dag_bev1 ASC ";
$ret1 = mysql_query($SQL1);
if (!$ret1) { echo( mysql_error()); }
else {
while ($row = mysql_fetch_array($ret1)) {
 $id = $row['id'];
 $fornamn = $row["fornamn"];
 $efternamn = $row["efternamn"];
 $medlemsnr = $row['medlemsnr'];
 $telnr = $row['telnr'];
 $mobilnr = $row['mobilnr'];
 $bryggplats = $row['bryggplatser.bryggplats'];
//Print mooring nr (second print column)
echo "<td>$bryggplats</td>";
//Print yacht owners' first name (third print column)
echo "<td>$fornamn</td>";
//Print yacht owners' last name (fourth print column)
echo "<td>$efternamn</td>";
//Print yacht owners' telephone number (fifth print column)
echo "<td>$telnr</td>";
//Print yacht owners' cell phone number (sixth print column)
echo "<td>$mobilnr</td>";
echo "</tr>";
}}
$dag = $dag + 60*60*24;
}
?>

The expected printout:
2011-05-08 62 Peter Taylor 0752-745041 0708-148319
2011-05-09 90 Sergio Gonzales 0738-990711 0708-990711
2011-05-10 91 Sergio Gonzales 0738-990711 0708-990711
2011-05-11 254 John Fitzgerald 0719-123456
This is how it is printed:
2011-05-08 62 Peter Taylor 7450410 0708-148319
2011-05-09 90 Sergio Gonzales 0738-990711 0738-990711
91 Sergio Gonzales 0738-990711 0738-990711
2011-05-10 90 Sergio Gonzales 0738-990711 0738-990711
91 Sergio Gonzales 0738-990711 0738-990711
2011-05-11 254 John Fitzgerald 0719-123456
When a name appears twice; i. e. on two dates, it comes up as doubles. That's not wanted.
How can I get it to print out the way I want it?

Randy Downs

Try using DISTINCT - Used to select unique records. Only unique values are returned.

SELECT DISTINCT(COLUMN) FROM TABLE

ASKER CERTIFIED SOLUTION

Guy Hengel [angelIII / a3]

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Lennart Ericson

ASKER

angelIII,
Thanks for your reply.
With this SQL sentence:
$SQL1 = " SELECT * FROM medlem_vakt_test LEFT JOIN bryggplatser ON medlem_vakt_test.medlemsnr = bryggplatser.medlemsnr WHERE (medlem_vakt_test.dagkod1 between '$dag2' AND '$dag') OR (medlem_vakt_test.dagkod2 between '$dag2' AND '$dag') GROUP BY medlem_vakt_test.dag_bev1, medlem_vakt_test.dag_bev2 ";
I get
2011-05-08 62 Peter Taylor 7450410 0708-148319
2011-05-09 90 Sergio Gonzales 0738-990711 0738-990711
2011-05-10 90 Sergio Gonzales 0738-990711 0738-990711
which is not wrong in itself, but I'd like to have the last line above like
2011-05-10 91 Sergio Gonzales 0738-990711 0738-990711
I. e. second column 91 instead of 90.
How could I achieve that?

Guy Hengel [angelIII / a3]

then you are grouping by the wrong columns, or not enough.
what column is that 90/91 coming from? add that to the group by ...

Lennart Ericson

ASKER

The column 90/91 is coming from is bryggpltser.bryggplats
If I group by bryggpltser.bryggplats, I get this outprint:
2011-05-08 62 Peter Taylor7450410 0708-148319
2011-05-09 90 Sergio Gonzales 0738-990711 0738-990711
91 Sergio Gonzales 0738-990711 0738-990711
2011-05-10 90 Sergio Gonzales 0738-990711 0738-990711
91 Sergio Gonzales 0738-990711 0738-990711
It is repeated twice. Please, give me an advice.

Guy Hengel [angelIII / a3]

>Please, give me an advice.
well, actually, I gave you some advice in giving the link to the article which describes the issue in general.

you need to find why it is "duplicated", aka which of the columns in the group by you need to remove to avoid what you consider a duplicate.

Lennart Ericson

ASKER

Thanks! Excellent article.