php error in javascript ( PHP Parse error: syntax error, unexpected T_STRING )

I have copied the exact source code of this site because I would like to use this example:
http://www.geocodezip.com/v3_GoogleEx_directions-draggable2Xml.html

I can't find out why I'm getting this error within this javascript:

PHP Parse error:  syntax error, unexpected T_STRING in /var/www/html/domain/test4.html on line 202

Why does my server try to execute javascript as php in this case starting at line 202? There is no

<?php ...

?>

in this javascript.  Really strange ..



seoptiAsked:
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Ray PaseurConnect With a Mentor Commented:
Interesting... That line in .htaccess says, Take all URLs with file names that end in .html or .php and feed them to the PHP parser.  I use that quite often when I have a colleague developer writing in Dreamweaver.  There may be something else wrong, however.  You might need to turn off the "short open tag" settings if you have any XML in the mix.
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seoptiAuthor Commented:
I found out it is because of this line in .htaccess:

Addhandler application/x-httpd-php .html .php

Seems I have to change it.
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seoptiAuthor Commented:
Thanks but when using:
php_flag short_open_tag off


all my other php scripts will not be parsed.
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hieloConnect With a Mentor Commented:
I agree with Ray. This line:

document.getElementById("polyline").value="<?xml version='1.0' encoding='UTF-8'?>\n<markers>\n";

is "seen/interpreted" as:
document.getElementById("polyline").value="<?phpxml version='1.0' encoding='UTF-8'?>\n<markers>\n";

because you do have short_tag_open set to true. So it will attempt to execute xml..., but that is NOT valid php syntax. If you cannot set it off, what you need to do is enclose the <?xml...?> in single quotes :

document.getElementById("polyline").value="<?php echo '<?xml version="1.0" encoding="UTF-8"?>'; ?>\n<markers>\n";

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