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How do you pass a C++ array element by reference?

Posted on 2011-03-14
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Last Modified: 2012-05-11
How do you pass an individual C++ array element by reference?  Is this possible?

Suppose you have the following class and array.  How would you pass an element of that array into some function while changing the actual element of that array as well as the members of that class instance?

class MyClass
{
     public:
          int member1;
          int member2;
          float member3;
};

MyClass myClassArray[ 10 ];

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Question by:CucumberBilly
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evilrix earned 500 total points
ID: 35131670
You mean something like this?
void foo(MyClass & c)
{
   // modify c
}


MyClass myClassArray[ 10 ];


foo(myClassArray[1]); // modify the 2nd element of the array.

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Author Closing Comment

by:CucumberBilly
ID: 35131855
Thanks, I didn't realize you could use the same reference operator in a function for array elements.
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Expert Comment

by:evilrix
ID: 35131923
A single array element is both semantically and syntactically identical to its scalar counterpart.
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