Little RegEx Help
Need a little help with the code search snippet that follows:
I need to break out the parts of the tokens, and I am having a hard time getting the regex right
WHat I need is:
TEST1 = Match Group 1
&ID=123&bob=yahoo&email=oi
for each of the ##...## passed in the string.
Here's what I got:
\#\#(.*?)\#\#
and it gets me the entire ##...##
I need to break out the parts of the tokens, and I am having a hard time getting the regex right
WHat I need is:
TEST1 = Match Group 1
&ID=123&bob=yahoo&email=oi
for each of the ##...## passed in the string.
Here's what I got:
\#\#(.*?)\#\#
and it gets me the entire ##...##
<div>
<h1>##TEST1&ID=123&bob=yahoo&email=oioiujij##</h1>
<h1>##TEST2##</h1>
<h1>##TEST3##</h1>
<h1>##TEST4&ID=123&bob=yahoo&email=oioiujij##</h1>
<h1>##TEST5##</h1>
</div>ASKER CERTIFIED SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Some regex tools don't support lookahead and lookbehind
But it should be fine in .NET
ASKER
nah, just tried it. on a page, and it doesn't work.
Using a slightly modified code from that site:
Dim tmpStr As New StringBuilder
Dim sourcestring As String = _Template
Dim re As Regex = New Regex("(?<=##)([^&\n]*?)(&
Dim mc As MatchCollection = re.Matches(sourcestring)
Dim mIdx As Integer = 0
For Each m As Match In mc
For groupIdx As Integer = 0 To m.Groups.Count - 1
tmpStr.Append(mIdx & ":" & re.GetGroupNames(groupIdx)
Next
mIdx = mIdx + 1
Next
Return tmpStr.ToString
returns me:
Using a slightly modified code from that site:
Dim tmpStr As New StringBuilder
Dim sourcestring As String = _Template
Dim re As Regex = New Regex("(?<=##)([^&\n]*?)(&
Dim mc As MatchCollection = re.Matches(sourcestring)
Dim mIdx As Integer = 0
For Each m As Match In mc
For groupIdx As Integer = 0 To m.Groups.Count - 1
tmpStr.Append(mIdx & ":" & re.GetGroupNames(groupIdx)
Next
mIdx = mIdx + 1
Next
Return tmpStr.ToString
returns me:
0:0=TEST1&ID=123&bob=yahoo&email=oioiujij<br />0:1=TEST1<br />0:2=&ID=123&bob=yahoo&email=oioiujij<br />1:0=</h1> <h1><br />1:1=</h1> <h1><br />1:2=<br />2:0=TEST2<br />2:1=TEST2<br />2:2=<br />3:0=</h1> <h1><br />3:1=</h1> <h1><br />3:2=<br />4:0=TEST3<br />4:1=TEST3<br />4:2=<br />5:0=</h1> <h1><br />5:1=</h1> <h1><br />5:2=<br />6:0=TEST4&ID=123&bob=yahoo&email=oioiujij<br />6:1=TEST4<br />6:2=&ID=123&bob=yahoo&email=oioiujij<br />7:0=</h1> <h1><br />7:1=</h1> <h1><br />7:2=<br />8:0=TEST5<br />8:1=TEST5<br />8:2=<br />
Try:
Dim re As Regex = New Regex(@"(?<=##)([^&\n]*?)(
Dim re As Regex = New Regex(@"(?<=##)([^&\n]*?)(
ASKER
error. 'Expression Expected'
Hmmm... I'm struggling a little with the syntax, because I don't program in that language.
You could try doubling the backslash instead:
Dim re As Regex = New Regex("(?<=##)([^&\\n]*?)(
You could try doubling the backslash instead:
Dim re As Regex = New Regex("(?<=##)([^&\\n]*?)(
@TerryAtOpus
"@" strings are C#-specific : )
@kevp75
Here's the output of TerryAtOpus' pattern in Expresso, a .NET-capable regex utility:
untitled.PNG
"@" strings are C#-specific : )
@kevp75
Here's the output of TerryAtOpus' pattern in Expresso, a .NET-capable regex utility:
untitled.PNG
SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
>> I understand it works in your software...
The point is that if it works in our software, it should work in your page because both are using the same regex engine.
The backslashes on the hash symbols should not be needed.
Glad you found a solution : )
The point is that if it works in our software, it should work in your page because both are using the same regex engine.
The backslashes on the hash symbols should not be needed.
Glad you found a solution : )
The pattern for the solution found by the asker:
"\#\#([^&\n]*?)(&.*?)?\#\#
is heavily based on my solution:
(?<=##)([^&\n]*?)(&.*?)?(?
therefore at least some points should be awarded.
This is because the core pattern of my pattern has been used:
([^&\n]*?)(&.*?)?
ps: Thanks kaufmed for the clarification regarding the @ symbol.
"\#\#([^&\n]*?)(&.*?)?\#\#
is heavily based on my solution:
(?<=##)([^&\n]*?)(&.*?)?(?
therefore at least some points should be awarded.
This is because the core pattern of my pattern has been used:
([^&\n]*?)(&.*?)?
ps: Thanks kaufmed for the clarification regarding the @ symbol.
ASKER
but you didn't answer the question, so I guess it will be dependant on what the moderators feel would be fair.
@Mods, I would agree to a point reduction...but definately not full points
@Mods, I would agree to a point reduction...but definately not full points
To clarify:
There is a typo here:
This is because the core pattern of my pattern has been used
It should read:
This is because the core part of my pattern has been used:
There is a typo here:
This is because the core pattern of my pattern has been used
It should read:
This is because the core part of my pattern has been used:
>> ps: Thanks kaufmed for the clarification regarding the @ symbol.
None required = )
Come on Terry... jump into VB programming. You know you want to ; )
None required = )
Come on Terry... jump into VB programming. You know you want to ; )
ASKER
;) I need to do the reverse...eventually... I will say this though... I love XML Literals
>> I will say this though... I love XML Literals
Indeed. They are pretty nifty = )
Indeed. They are pretty nifty = )
ASKER
can we reduce the points? I'll admit he helped, however it didn't end up being the solution?
ASKER
:) yeah.... that was a DOH! moment ;)
ASKER
ultimate solution
ASKER