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Stored Procedure return variable

Posted on 2011-03-14
2
194 Views
Last Modified: 2012-05-11
I'm trying to take the ID from one stored procedure INSERT to another stored procedure INSERT.  My first stored procedure is actually inserting the record, but it is inserting NULL into the 2nd parameter in the next stored procedure that tries to use the inserted ID. My 2 execute lines are below, and the first stored procedure is pasted into the code snippet below.

Exec spDCUsers_AddCreditApplication @dcca_firstname,@dcca_middleinitial,@dcca_lastname,@dcca_ssn,@dcca_dob,@dcca_phonehome,@dcca_phonework,@dcca_email,@dcca_address1,@dcca_address2,@dcca_city,@dcca_state, @dcca_zip,@dcca_timeataddressyrs,@dcca_timeataddressmos,@dcca_typeofresidence,@dcca_typeofincome,@dcca_frequency,@dcca_grossamount, @dcca_rentpayment,@dcca_selfemployedorretired,@dcca_employer,@dcca_empaddress1,@dcca_empaddress2,@dcca_empcity,@dcca_empstate, @dcca_empzip, @dcca_empcountry,@dcca_occupation,@dcca_timeonjobyrs, @dcca_timeonjobmos, @CreditAppId OUTPUT

Exec spDCUsers_AddCreditApplicationProductVersion @UserId, @CreditAppId, @dccapv_productid
USE [drivecore]
GO
/****** Object:  StoredProcedure [saturation1].[spDCUsers_AddCreditApplication]    Script Date: 03/14/2011 19:43:00 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER PROCEDURE [saturation1].[spDCUsers_AddCreditApplication]
(

@dcca_firstname nvarchar(50),
@dcca_middleinitial nvarchar(1),
@dcca_lastname nvarchar(50),
@dcca_ssn nvarchar(11),
@dcca_dob nvarchar(10),
@dcca_phonehome nvarchar(20),
@dcca_phonework nvarchar(20),
@dcca_email nvarchar(75),
@dcca_address1 nvarchar(100),
@dcca_address2 nvarchar(100),
@dcca_city nvarchar(50),
@dcca_state nvarchar(2),
@dcca_zip nvarchar(10),
@dcca_timeataddressyrs nvarchar(2),
@dcca_timeataddressmos nvarchar(2),
@dcca_typeofresidence nvarchar(20),
@dcca_typeofincome nvarchar(30),
@dcca_frequency nvarchar(20),
@dcca_grossamount nvarchar(8),
@dcca_rentpayment nvarchar(10),
@dcca_selfemployedorretired nvarchar(15),
@dcca_employer nvarchar(100),
@dcca_empaddress1 nvarchar(50),
@dcca_empaddress2 nvarchar(50),
@dcca_empcity nvarchar(50),
@dcca_empstate nvarchar(2),
@dcca_empzip nvarchar(10),
@dcca_empcountry nvarchar(50),
@dcca_occupation nvarchar(75),
@dcca_timeonjobyrs nvarchar(2),
@dcca_timeonjobmos nvarchar(2), 
@CreditAppId INT OUTPUT
)

AS
BEGIN

INSERT INTO [tblDCCreditApplication](
           
[dcca_firstname],
[dcca_middleinitial],
[dcca_lastname],
[dcca_ssn],
[dcca_dob],
[dcca_phonehome],
[dcca_phonework],
[dcca_email],
[dcca_address1], 
[dcca_address2],
[dcca_city],
[dcca_state],
[dcca_zip],
[dcca_timeataddressyrs],
[dcca_timeataddressmos],
[dcca_typeofresidence],
[dcca_typeofincome],
[dcca_frequency],
[dcca_grossamount], 
[dcca_rentpayment],
[dcca_selfemployedorretired],
[dcca_employer],
[dcca_empaddress1], 
[dcca_empaddress2],
[dcca_empcity],
[dcca_empstate],
[dcca_empzip],
[dcca_empcountry],
[dcca_occupation],
[dcca_timeonjobyrs], 
[dcca_timeonjobmos]
)

VALUES (
@dcca_firstname,
@dcca_middleinitial,
@dcca_lastname,
@dcca_ssn,
@dcca_dob,
@dcca_phonehome,
@dcca_phonework,
@dcca_email,
@dcca_address1,
@dcca_address2,
@dcca_city,
@dcca_state, 
@dcca_zip,
@dcca_timeataddressyrs,
@dcca_timeataddressmos,
@dcca_typeofresidence,
@dcca_typeofincome,
@dcca_frequency,
@dcca_grossamount, 
@dcca_rentpayment,
@dcca_selfemployedorretired,
@dcca_employer,
@dcca_empaddress1,
@dcca_empaddress2,
@dcca_empcity,
@dcca_empstate, 
@dcca_empzip, 
@dcca_empcountry,
@dcca_occupation,
@dcca_timeonjobyrs,
@dcca_timeonjobmos
);

DECLARE  @ApplicationId INT          
SET @ApplicationId = SCOPE_IDENTITY();
      

END

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Question by:saturation
2 Comments
 
LVL 29

Accepted Solution

by:
Paul Jackson earned 500 total points
ID: 35134694
Change these lines in your first stored procedure :

DECLARE  @ApplicationId INT          
SET @ApplicationId = SCOPE_IDENTITY();

to
SET @CreditAppId = SCOPE_IDENTITY();
0
 

Author Comment

by:saturation
ID: 35134706
Excellent.   Thanks jacko!
0

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