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Check the program start time

Posted on 2011-03-16
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Last Modified: 2012-05-11
Hi, I run an application program yesterday, it is still running today. I want to know when the program begun. Is there a command for that?

Thanks.
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Question by:zhshqzyc
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by:woolmilkporc
ID: 35149022
ps -fo etime -p pid_of_your_process

This will show you the elapsed time as

DD-HH:MM:SS

so you can easily calculate the start time.

I assume you know how to get the PID of a running process?

wmp
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by:zhshqzyc
ID: 35149088
But I don't know how to get the pid? Please advise me.
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by:woolmilkporc
ID: 35149127
Take the second column of

ps -ef | grep programname

I just hope you do know the name of your program (at least part of it) 'coz I will not be able to help you there.
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by:zhshqzyc
ID: 35149250
[testme@saguaro4 ~]$ ps -ef | grep saguaro
markv    12557 12530  0 Feb16 pts/8    00:13:49 emacs -cr maroon -ms blue -bg gray20 -fg grey90 -geometry 73x77+507+0 -font -misc-fixed-medium-r-normal--14-*-*-*-*-*-iso8859-1 -name saguaro emacs
testme   15128  5776  0 09:00 pts/4    00:00:00 grep saguaro
[testme@saguaro4 ~]$ 

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The program is called "saguaro", so is the pid=15128?
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woolmilkporc earned 50 total points
ID: 35149270
No, that's the PID of your "grep" search.

The PID is 12557
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Author Comment

by:zhshqzyc
ID: 35323797
Can we  just use one line or a batch file to get it?
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Expert Comment

by:woolmilkporc
ID: 35324669
You asked for it!

Save the following script in a file named e.g. pstime, issue "chmod +x pstime".

Now determine the id of the process in question (PID) and run the script with

pstime PID

e.g.

pstime 12557

#!/bin/bash
ETIME=$(ps -f -o etime= -p $1)
if [[ -z $ETIME ]]; then
 echo "Process does not exist!"
  else
   echo "Start Time of Process with PID $1 is:"
    if echo $ETIME | grep -q "-" ; then
     date -d "01/01/1970+$(($(date +%s)-$(echo $ETIME | awk -F"[:-]" '{print ($1*86400)+($2*3600)+($3*60)+$4}'))) seconds"
    else
     date -d "01/01/1970+$(($(date +%s)-$(echo $ETIME | awk -F"[:]" '{print ($1*3600)+($2*60)+$3}'))) seconds"
    fi
fi

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