Insert an incremented value in SQL?

Hi.  I have a stored procedure that returns a recordset of customers from two customer tables.  I gather the records into a single temp table, as shown in the attached code.

First, the final resultset must be ordered by customer name.  Next, I have a column called 'GroupID'.  'GroupID' needs to be set to an incremented integer --  however, it needs increment every 25 rows.  So, 'GroupID' for the first 25 rows returned needs to be set to 1, the next 25 rows need to be set to 2, and so on for the next 25000+ rows.

I hope I am being clear ... I have simplified my existing procedure to a bare minimum in the example attached.

Any suggestions about how to do this in MS SQL?
Thanks.

create table #Temp1
   (TEMP1_Id int IDENTITY (1, 1) NOT NULL,
    Cust_Name  varchar(50),
    GroupID    integer null)
		 
insert into #Temp1 (Cust_Name)
    Select Cust_Name from CustTable1

insert into #Temp1 (Cust_Name)
    Select Cust_Name from CustTable2
	
------------------------------------------
-- need some UPDATE #Temp1 code in here ...
-- probably need to 'order by Cust_Name' here 
------------------------------------------

-- return the final resultset ...
select * from #Temp1
order by Cust_Name

Open in new window

Rob RudloffIT Development SpecialistAsked:
Who is Participating?
 
HainKurtConnect With a Mentor Sr. System AnalystCommented:
no need for identity, temptable etc etc... try this

with Cust as (
Select 1 ord, Cust_Name from CustTable1
union
Select 2 ord, Cust_Name from CustTable2
)
select rn, rn/25 as GroupID, cust_name
from (select *, ROW_NUMBER() over (Order by ord, cust_name) rn from cust) x
0
 
devlab2012Commented:
you cannot do it using IDENTITY. You can create a stored procedure for inserting records. In the stored procedure, count the number of records and set the value of groupid based upon the total number of rows/25.
0
 
LeDaoukConnect With a Mentor Commented:
also before the last select you can add the attached code to update the group ID field
DECLARE DECLARE  @Min  numeric,@Max  numeric, @Count  numeric,@Seq  numeric, @TempSeq  numeric
	SET @Count = (Select count(TEMP1_Id) From #Temp1)
	SET @Min = (SELECT MIN TEMP1_Id FROM  #Temp1)
	SET @Max = (SELECT MIN TEMP1_Id FROM  #Temp1)
	SET @Seq = 1
	SET @TempSeq = 1
	WHILE @Min <= @Max
		BEGIN
			UPDATE #TEMP1 SET GroupID = @Seq WHERE Temp1_ID = @Min
			SET @Seq = 1
			SET @TempSeq = @TempSeq +1
			IF @TempSeq  = 26
			BEGIN
				SET @TempSeq = 1
				SET @Seq = @Seq +1 
			END
			Set @Min = @Min+1

		End

Open in new window

0
 
Rob RudloffIT Development SpecialistAuthor Commented:
Thanks -- I started with LaDaouk's suggestions, and ended up using HainKurt's idea.

With HainKurts code, I started with:  
select *, ((ROW_NUMBER() over (Order by cust_name))/25) as GroupID    from #temp1

Open in new window

This presented rows 1-24 in group 0, and 25-49 in group 1.

After that I adjusted it a bit, so that rows 1-25 were in group 1, rows 26-50 in group 2:
select *, (((ROW_NUMBER() over (Order by cust_name))- 1)/25) + 1 as GroupID    from #temp1

Open in new window


Thanks everyone.
0
All Courses

From novice to tech pro — start learning today.