• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 385
  • Last Modified:

VBA for Excel Spreadsheet

Hello,

Could someone tell me how to find all of the records in a column that start with the letter 'A', and if they start with 'A' do a mid function.  =mid(A2, 2, 5)

Thanks.
0
erp1022
Asked:
erp1022
2 Solutions
 
jppintoCommented:
You could put a formula on a second column like this:

=IF(LEFT(A1,1)="A",MID(A1, 2, 5),"")

This will extract the information that you want. Then you could Autofilter this column to list all excepet blanks and copy the result to a new sheet.

jppinto
0
 
erp1022Author Commented:
I actually need VBA for this. It's for an end user and I would like for them to be able to just press a button. (run a macro)
0
 
MeLindaJohnsonCommented:
Record a macro. -->Developer tab, Record Macro
Walk through the steps. (Find the A, and the replace with what you what)
Stop the macro
This will produce the vba code for you.--Developer tab, Visual Basic, vbaproject(personal.xlsb)
Then you can copy the macro code into their personal.xlsb file (after tweeking a little bit probably
and then reference it on the toolbar when you create the button -> right click on toolbar , customize quick access toolbar, choose commands from: choose macros-> choose the name of the macro and add it, click ok.
Good luck
0
NEW Veeam Backup for Microsoft Office 365 1.5

With Office 365, it’s your data and your responsibility to protect it. NEW Veeam Backup for Microsoft Office 365 eliminates the risk of losing access to your Office 365 data.

 
erp1022Author Commented:
That won't work either. There will be a different number of records in my file each month. What I need is VBA that will go through the whole column and if it begins with an A, strip it off, then do the mid function.
0
 
MeLindaJohnsonCommented:
If you highlight the whole column before performing the find function, that should help, that way it will only look in that column
0
 
MeLindaJohnsonCommented:
please provide an excel file
0
 
erp1022Author Commented:
Here's what the VBA looks like after recording the macro. In the 2nd to last and last line where it says 'Range' can I just change that to B2:B2 and that will take care of the whole column no matter how many records?
Columns("B:B").Select
    Selection.Insert Shift:=xlToRight
    Range("B2").Select
    ActiveCell.FormulaR1C1 = "=IF(LEFT(RC[1],1)=""A"", MID(RC[1], 2, 5), RC[1])"
    Range("B2").Select
    Selection.AutoFill Destination:=Range("B2:B2204")
    Range("B2:B2204").Select
End Sub
0
 
MeLindaJohnsonCommented:
Not B2:B2, but you could do
B2:B(choose a number that you think would be the maximum number of rows like 60,000)
0
 
erp1022Author Commented:
There should be some function, I'm not a VBA developer (obviously) but I think it's transpose or array or count? Something that will count the actual number of records and update only that range. I really don't know how many records my file will be and don't like putting in a random number to account for the range.
0
 
martykCommented:
See if this works for you.

 
' What I need is VBA that will go through the whole column
' and if it begins with an A, strip it off, then do the mid function.
'  =mid(A2, 2, 5)

Public Sub DeletePrefix()

For Each i In Sheets("sheet1").Range("A:A") ' entire 1st column independent of max rows
    If Mid(i.Value, 1, 1) = "A" Then
        i.Value = Mid(i.Value, 2, 5) 'NOTE: remove last argument to preserve all but the first character
    End If
Next i

End Sub

Open in new window


Marty
0
 
erp1022Author Commented:
Sorry for the delay, I just got back from vacation. I will test this either later on today or early tomorrow.

Thanks.
0

Featured Post

Independent Software Vendors: We Want Your Opinion

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Tackle projects and never again get stuck behind a technical roadblock.
Join Now