Solved

java concatenation and special characters

Posted on 2011-03-16
2
399 Views
Last Modified: 2012-05-11
a,b,c are variables.
And I want to concatenate them. So I have two related questions:

1- If I do the following, is it gonna process "\n" as a new line character or literally \n? If literally \n, then how can I make it processed as new line character?

2- So I have variable a in my hand. And I want to add b and c as a prefix to a not a suffix. I mean in the beginning of what is in a now. Is this gonna work? If not how can I make it?

a = b + "\n" + c + a;

Open in new window

0
Comment
Question by:Tolgar
2 Comments
 
LVL 86

Accepted Solution

by:
CEHJ earned 500 total points
ID: 35152114
That newline will be interpreted as an escape sequence so you'll actually get a newline in the String. Print it out and you'll see
0
 
LVL 92

Expert Comment

by:objects
ID: 35152137
1. It will be treated as a new line char. Generally better to use System.getProperty("line.separator") as it will be line seperator for the platform you are running on
2. you can change the order of concatentation however you like
0

Featured Post

Master Your Team's Linux and Cloud Stack!

The average business loses $13.5M per year to ineffective training (per 1,000 employees). Keep ahead of the competition and combine in-person quality with online cost and flexibility by training with Linux Academy.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
groupSum6 challenge 6 86
Apps blocked by Java 9 79
java stored proc example 9 29
hibernate example issues from command prompt 10 41
For customizing the look of your lightweight component and making it look lucid like it was made of glass. Or: how to make your component more Apple-ish ;) This tip assumes your component to be of rectangular shape and completely opaque. (COD…
INTRODUCTION Working with files is a moderately common task in Java.  For most projects hard coding the file names, using parameters in configuration files, or using command-line arguments is sufficient.   However, when your application has vi…
Viewers learn about the scanner class in this video and are introduced to receiving user input for their programs. Additionally, objects, conditional statements, and loops are used to help reinforce the concepts. Introduce Scanner class: Importing…
Viewers will learn one way to get user input in Java. Introduce the Scanner object: Declare the variable that stores the user input: An example prompting the user for input: Methods you need to invoke in order to properly get  user input:

770 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question