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how to make replacement in a string

Posted on 2011-03-16
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Last Modified: 2012-05-11
Hi,
I have a string in Java and I would like to add "m" to the beginning of all instances of these numbers in the string. (numbers can be either 5, 6 or 7 digits)

e.g.
System.out.println(java.lang.String list); 

'12345, 123456, 1234567, 333333, 444444'

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Now I want to make list:

System.out.println(java.lang.String list);

'm12345,m123456,m1234567,m333333,m444444'

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How can I make it?

Thanks,
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Question by:Tolgar
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8 Comments
 
LVL 47

Expert Comment

by:for_yan
ID: 35153583
you can say

String [] s1 = s.split(",");

String s0 = "";

for(int j=0; j<s1.length; j++)s0+= "m" + s1[j] + ",";

s0 = s0.substring(0,s0.length()-1);
0
 
LVL 92

Expert Comment

by:objects
ID: 35153584
String[] numbers = s.split(",");
StringBuilder sb = new StringBuilder();
for (String number : numbers) {
   sb.append('m');
   sb.append(number);
   sb.append(',');
}
String newstring = sb.substring(0, sb.length()-1).toString();
0
 
LVL 47

Expert Comment

by:for_yan
ID: 35153586


String [] s1 = s.split(",");

String s0 = "";

for(int j=0; j<s1.length; j++)s0+= "m" + s1[j] .trim()+ ",";

s0 = s0.substring(0,s0.length()-1);
0
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LVL 11

Assisted Solution

by:JoeNuvo
JoeNuvo earned 200 total points
ID: 35153587
if the pattern of data always exact as your given
(seperate by comma and one space)

you can do   list =  "m" + list.replace(", " , ",m");
0
 
LVL 24

Assisted Solution

by:jimyX
jimyX earned 200 total points
ID: 35153610
You can use ReplaceAll and add the new char "m" at the beginning to your string, as follows:

YourString = "m" + YourString.replaceall(" ","m");
0
 
LVL 36

Accepted Solution

by:
mccarl earned 1600 total points
ID: 35153631
And just another way to skin the cat...

list = list.replaceAll("(\\d+)", "m$1");

If you also did what to explicitly remove the whitespace between the comma, as your above example shows, then it is a simple extension to the above...

list = list.replaceAll("\\s*(\\d+)", "m$1");

I know, some people may say that using regular expressions can be overkill, or have less performance than other methods, but if it fits for your particular situation, I say use them, it certainly makes it a lot more simple, and once you learn a bit of regex syntax, I think it makes it more clear as to your intentions... The above is quite clearly saying, replace all groups of one or more digits with an m followed by those digits.

Also, it allows you to extend the above to make it as strict as you like, etc.
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LVL 24

Expert Comment

by:jimyX
ID: 35153894
@ Tolgar
Please ignore my post.

@ JoeNuvo
Next time I will be faster :-)
0
 

Author Closing Comment

by:Tolgar
ID: 35156155
One line short suggestions are generally better than other approaches which include loops in them. That's why I picked these three suggestions. And regexp one is more clear as mentioned.
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