SQL Query - Group by day

You need to group by day on Datestamp field ? right?

try this
Select X.DateStamp ,X.incidents
From (
Select DateStamp , count(*) as incidents from IncidentReport
Group by DateStamp ) X
order by X.incidents desc


OR TRY THIS

Select X.DateStamp ,X.incidents
From (
Select DateStamp , count(*) as incidents from IncidentReport
Group by DateStamp ) X
order by X.incidents asc

You can think of something like this:
Select ROWNUM, IncidentDate, Count(IncidentDate) from YourTable Group by IncidentDate order by IncidentDate

so something like this?

SELECT *, ROWNUM, TimeOccured AS Expr1, COUNT(TimeOccured) AS Expr2
FROM  IncidentReport
GROUP BY TimeOccured
ORDER BY TimeOccured

Although it's having a problem recognizing ROWNUM

Try:

SELECT *, ROW_Number, TimeOccured AS Expr1, COUNT(TimeOccured) AS Expr2
FROM  IncidentReport
GROUP BY TimeOccured
ORDER BY TimeOccured

same thing, having a problem at ROW_Number

what is rownum anyways? a variable to pass data back?

It puts a serial number to your rows (1, 2, 3, ...):

OK, let's try this please:

SELECT *, ROW_NUMBER() OVER (ORDER BY TimeOccured) AS n, TimeOccured AS Expr1, COUNT(TimeOccured) AS Expr2
FROM  IncidentReport
GROUP BY TimeOccured
ORDER BY TimeOccured

order by will not work with gorup by

Select ROW_NUMBER() OVER (ORDER BY TimeOccured) AS n,X.TimeOccured ,x.incedences
SELECT TimeOccured ,  TimeOccured AS Expr1, COUNT(TimeOccured) AS incedences
FROM  IncidentReport
GROUP BY TimeOccured ) X
ORDER BY X.TimeOccured

err,, no ROW_NUMBER is don't think is anything
and I'm passing it into a dataset, will this syntax work like that?

trying it this way, still blowing up
SELECT TimeOccured
FROM  (SELECT TimeOccured, COUNT(*)
               FROM   IncidentReport
               GROUP BY DateStamp)
ORDER BY incidents

try thia

SELECT X.TimeOccured,X.incidents
FROM  (SELECT TimeOccured, COUNT(*) as incidents
               FROM   IncidentReport
               GROUP BY DateStamp) X
ORDER BY X.incidents

What about this:
Select TimeOccured, Count(TimeOccured)
From IncidentReport
Group by TimeOccured
Order by TimeOccured

ok, getting somewhere

this executes

SELECT TimeOccured, COUNT(TimeOccured) AS IncidentCount
FROM  IncidentReport
GROUP BY TimeOccured
ORDER BY IncidentCount DESC

but something is wrong, I think maybe it's not getting the full day, or maybe I have to include the day/time and not just the date

If you are working in SQL Server 2008, try this.

SELECT CONVERT(DATE,TimeOccured) AS TimeOccured, 
         COUNT(TimeOccured)        AS IncidentCount 
    FROM IncidentReport 
GROUP BY CONVERT(DATE,TimeOccured) 
ORDER BY IncidentCount DESC

Select allOpen in new window

If SQL Server 2005 or less, try this.

SELECT DATEADD(dd,0,DATEDIFF(dd,0,TimeOccured)) AS TimeOccured, 
         COUNT(TimeOccured)                       AS IncidentCount 
    FROM IncidentReport 
GROUP BY DATEADD(dd,0,DATEDIFF(dd,0,TimeOccured)) 
ORDER BY IncidentCount DESC

Select allOpen in new window

Set the field TimeOccured datatype to Date.

OH YA!!!!!!!!!!

pratima, you the man!!!

this works great!

SELECT TOP (100) CONVERT(varchar(10), TimeOccured, 101) AS TimeOccuredDay, COUNT(TimeOccured) AS IncidentCount
FROM  IncidentReport
GROUP BY CONVERT(varchar(10), TimeOccured, 101)
ORDER BY IncidentCount DESC


I only have one last questio. I'm trying to pull IncidentReportID

but I try this

SELECT TOP (100) CONVERT(varchar(10), TimeOccured, 101) AS TimeOccuredDay, COUNT(TimeOccured) AS IncidentCount, IncidentReportID
FROM  IncidentReport
GROUP BY CONVERT(varchar(10), TimeOccured, 101)
ORDER BY IncidentCount DESC


but it blows up. is this possible to do?

SELECT TOP (100) CONVERT(varchar(10), TimeOccured, 101) AS TimeOccuredDay, COUNT(TimeOccured) AS IncidentCount, IncidentReportID
FROM  IncidentReport
GROUP BY CONVERT(varchar(10), TimeOccured, 101),IncidentReportID

ORDER BY IncidentCount DESC