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cfif, listLast, need to find a char at the end of a variable

Posted on 2011-03-17
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Last Modified: 2012-05-11
i'm looping through a list and outputting variables like so:

<cfloop list="#ColList#" index="ColList">
<cfoutput>#ColList#</cfoutput>
</cfloop>

each variable which is outputted ends with either _1 or _2

what i need is this:

CFIF variable ends in _1
THEN do this
IF it ends in _2
THEN do this
otherwise just do this.


thats the plain english version. :-) can anyone helpo me do this?

thanks
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Question by:bede123
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6 Comments
 
LVL 52

Expert Comment

by:_agx_
ID: 35161328
First, make sure you use different variables name for  the "list" and "index". Then assuming the values always contain

<cfloop list="#ColList#" index="theItem">
    <cfset suffix = listLast(theItem, "_")>
    <cfif suffix eq "1">
         it's 1. do something
    <cfelseif suffix eq "2">
         it's 2. do something else
     <cfelse>
          not 1 or 2. do something else
     </cfif>
</cfloop>
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LVL 52

Expert Comment

by:_agx_
ID: 35161383
Oops, posted too soon.  I meant to say: assuming the values always contain a "_", then use the code above. Otherwise, you might want to add validation of the listLen
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LVL 1

Author Comment

by:bede123
ID: 35161403
That's perfect thanks. I can ensure that _ does exist by validating a couple of steps prior to this one.

I've been trying all night to put this together! I didn't even have Suffix in my version! :-)
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LVL 52

Accepted Solution

by:
_agx_ earned 2000 total points
ID: 35161457
I chose to create a separate variable named "suffix" for readability.  But technically you could just use the listLast() function twice.

  <cfif listLast(theItem, "_") eq "1">
         it's 1. do something
    <cfelseif listLast(theItem, "_") eq "2">
         it's 2. do something else
     <cfelse>
          not 1 or 2. do something else
     </cfif>
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LVL 1

Author Comment

by:bede123
ID: 35164887
oh i see, i thought.... oh never mind....                      so much to learn!

i decided to use the one without the suffix.

many thanks (again)

z
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LVL 52

Expert Comment

by:_agx_
ID: 35166715
Welcome :)
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