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Yes - more specifically, the default constructor is called - if you need another ctor, you can call it in the derived class' ctor's initializer list. See also e.g. <a href="http://publib.boulder.ibm.com/infocenter/comphelp/v8v101/index.jsp?topic=%2Fcom.ibm.xlcpp8a.doc%2Flanguage%2Fref%2Fcplr388.htm" rel="ugc nofollow">http://publib.boulder.ibm.com/infocenter/comphelp/v8v101/index.jsp?topic=%2Fcom.ibm.xlcpp8a.doc%2Flanguage%2Fref%2Fcplr388.htm</a>&nbsp;(&quot;Initializing base classes and members (C++ only)&quot;): &quot;If you do not explicitly initialize a base class or member that has constructors by calling a constructor, the compiler automatically initializes the base class or member with a default constructor.&quot;
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Yes - more specifically, the default constructor is called - if you need another ctor, you can call it in the derived class' ctor's initializer list. See also e.g. http://publib.boulder.ibm.com/infocenter/comphelp/v8v101/index.jsp?topic=%2Fcom.ibm.xlcpp8a.doc%2Flanguage%2Fref%2Fcplr388.htm [http://publib.boulder.ibm.com/infocenter/comphelp/v8v101/index.jsp?topic=%2Fcom.ibm.xlcpp8a.doc%2Flanguage%2Fref%2Fcplr388.htm] ("Initializing base classes and members (C++ only)"): "If you do not explicitly initialize a base class or member that has constructors by calling a constructor, the compiler automatically initializes the base class or member with a default constructor."

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in C++, does a derived class constructor &quot;automatically&quot; call the base class constructor?
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in C++, does a derived class constructor "automatically" call the base class constructor?

derived class constructor

C++ is an intermediate-level general-purpose programming language, not to be confused with C or C#. It was developed as a set of extensions to the C programming language to improve type-safety and add support for automatic resource management, object-orientation, generic programming, and exception handling, among other features.