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# Javascript replace...Need to replace all at once.

Posted on 2011-03-18
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I have a string of numbers called "sTime".   The problem I'm having is that it's replacing my numbers in a sequential order, so if I have a 0 that gets replaced by a 6, when it goes down another 6 rows of code, it's replacing the 6 with a 2.   I only want it to replace it once, even though that number may appear more than once in the string.  For example,

00112 needs to be 66778 rather than 22334, which is wrong.   Help?   My code is below.

sTime = sTime.replace(/0/g,'6');
sTime = sTime.replace(/1/g,'7');
sTime = sTime.replace(/2/g,'8');
sTime = sTime.replace(/3/g,'9');
sTime = sTime.replace(/4/g,'0');
sTime = sTime.replace(/5/g,'1');
sTime = sTime.replace(/6/g,'2');
sTime = sTime.replace(/7/g,'3');
sTime = sTime.replace(/8/g,'4');
sTime = sTime.replace(/9/g,'5');
0
Question by:saturation
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LVL 82

Accepted Solution

leakim971 earned 500 total points
ID: 35168996
Use : sTime.replace(/\d/g, function(\$1) { return [6,7,8,9,0,1,2,3,4,5][\$1]; })
``````<html><head><script>

sTime = "00112";
alert(  sTime.replace(/\d/g, function(\$1) { return [6,7,8,9,0,1,2,3,4,5][\$1]; })  );

</script><body></body></html>
``````
0

LVL 82

Expert Comment

ID: 35169018
work too :
``````sTime = sTime.replace(/\d/g, function(\$1) { return (-\$1-6) * -1; });
``````

or again :
``````sTime = sTime.replace(/\d/g, function(\$1) { return Math.abs(-\$1-6); });
``````
0

Author Closing Comment

ID: 35169049
Great...Now I have another similar question related to this.
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