mustish1
asked on
Syntax Error
Hi guys: Can any one please tell me why it gives syntax error on that line ? Thanks.
celsustempValue = calcSensus(getFahrcalcvalu e);
-------------------------- ---------- --------
#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main()
{
double getFahrcalcvalue = 0.00;
double celsustempValue = 0.00;
double calcFahr()
{
double FarTemp
cout << "Enter Fahrenheit temperature==>";
cin >> FarTemp;
return(FarTemp);
}
double calcSensus(double CencTemp)
{
double FarTempValue = 0.00;
FarTempValue = CencTemp;
CencTemp = 50 / 9.0 * (FarTempValue -32.0);
return(CencTemp);
}
getFahrcalcvalue = calcFahr();
celsustempValue = calcSensus(getFahrcalcvalu e);
cout << "Celsius temperature==>" << celsustempValue << endl;
system("pause");
return 0;
}
celsustempValue = calcSensus(getFahrcalcvalu
--------------------------
#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main()
{
double getFahrcalcvalue = 0.00;
double celsustempValue = 0.00;
double calcFahr()
{
double FarTemp
cout << "Enter Fahrenheit temperature==>";
cin >> FarTemp;
return(FarTemp);
}
double calcSensus(double CencTemp)
{
double FarTempValue = 0.00;
FarTempValue = CencTemp;
CencTemp = 50 / 9.0 * (FarTempValue -32.0);
return(CencTemp);
}
getFahrcalcvalue = calcFahr();
celsustempValue = calcSensus(getFahrcalcvalu
cout << "Celsius temperature==>" << celsustempValue << endl;
system("pause");
return 0;
}
SOLUTION
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SOLUTION
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ASKER CERTIFIED SOLUTION
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Factor of 10 off:
CencTemp = 50 / 9.0 * (FarTempValue -32.0);
Try:CencTemp = 5/ 9.0 * (FarTempValue -32.0);
ASKER
Thanks to every body.
And you don't need the () on the return.