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PHP DEFINE literal in a double quoted string

Posted on 2011-03-21
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Last Modified: 2012-05-11
Simple $variables expand if they're in a DOUBLE quoted string
ex: "Today's Date: $DateVariable"

if i have a DEFINE literal    is there any syntax escapement to get them to expand (be replaced) in a double quoted string?

DEFINE  DAILY_MODE =1

echo "The mode value is  DAILY_MODE ";

otherwise:
echo "The mode value is ".  DAILY_MODE;

thanks
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Question by:willsherwood
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3 Comments
 
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Accepted Solution

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Beverley Portlock earned 250 total points
ID: 35181333
Stick with echo "The mode value is ".  DAILY_MODE;. Variable expansion is for variables and literals are not variables
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Assisted Solution

by:Scott Madeira
Scott Madeira earned 250 total points
ID: 35181334
Not that I am aware of or could find online.  I think you are stuck with option 2: echo "The mode value is ".  DAILY_MODE;
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Author Closing Comment

by:willsherwood
ID: 35181452
thanks all
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