How to calcuate time duration from 2 time strings?
Hello All,
I am having writers block. I would like to calculate the time duration from 2 strings that are input by the user. I know I need to convert the strings to date/time format or integer. The time strings would look something like this; start time - 10:35:22.189 and end time - 11:41:12.120. Also, notice I need milliseconds. Because I am working with just time, I am having trouble determining which calendar/date function to use because they involve using the date as well. Instead of date, the user is entering the Day of Year, so it is any integer that is within the 1 to 365 days. So, the timestamp format would be 219/10:35:22.189. What is the best method to use for this calculation? Any resources, recommendations or examples would be very helpful. Thank you.
I am having writers block. I would like to calculate the time duration from 2 strings that are input by the user. I know I need to convert the strings to date/time format or integer. The time strings would look something like this; start time - 10:35:22.189 and end time - 11:41:12.120. Also, notice I need milliseconds. Because I am working with just time, I am having trouble determining which calendar/date function to use because they involve using the date as well. Instead of date, the user is entering the Day of Year, so it is any integer that is within the 1 to 365 days. So, the timestamp format would be 219/10:35:22.189. What is the best method to use for this calculation? Any resources, recommendations or examples would be very helpful. Thank you.
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Oh sorry - if you want all milliseconds, it's better to use for_yan's method, which can be simplified:
public static long timeDiff(String t1, String t2) throws ParseException {
DateFormat df = new SimpleDateFormat("HH:mm:ss.S");
return df.parse(t2).getTime() - df.parse(t1).getTime();
}
With clearer naming:
public static long timeDiff(String startTime, String endTime) throws ParseException {
DateFormat df = new SimpleDateFormat("HH:mm:ss.S");
return df.parse(endTime).getTime() - df.parse(startTime).getTime();
}ASKER
Thank you for your quick responses.
In using the end.getTime() - start.getTime() formula, this turns the time difference in milliseconds, correct? If I need to display the time format HH:mm:ss.SSS, I would need to add logic that converts the milliseconds to hour, minutes and seconds.
In using the end.getTime() - start.getTime() formula, this turns the time difference in milliseconds, correct? If I need to display the time format HH:mm:ss.SSS, I would need to add logic that converts the milliseconds to hour, minutes and seconds.
ASKER
One more question. Should I be concerned that when I am only working with time, the date is defaulted to 1/1/1970?
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>> If I need to display the time format HH:mm:ss.SSS, I would need to add logic that converts the milliseconds to hour, minutes and seconds.
You could use the code that i originally gave you
You could use the code that i originally gave you
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You can actually just use the same DateFormat and do
String hms_ms = df.format(new Date(diff));You would think so, but in fact at least SimpleDateFormat (don't now about
when you format
SimpleDateFormat f = new SimpleDateFormat("hh:mm:ss
Date d1 = f.parse(s1,new ParsePosition(0));
Date d2 = f.parse(s2,new ParsePosition(0));
long msec = d2.getTime() - d1.getTime();
System.out.println("msec:"
Date d3 = new Date(msec );
System.out.println("date: " + d3);
String ss = f.format(d3);
System.out.println("ss:" + ss);
returns
17:05:49.931
instead of 01:05:49.931
even though msec returns correctly:
msec: 3949931
(a little bit more than an hour ofr those two points you specified).
Don't understand how it can be
You would think so, but in fact it does not work this way:
at least with SimpleDateFormat
when you format it like that:
SimpleDateFormat f = new SimpleDateFormat("hh:mm:ss
Date d1 = f.parse(s1,new ParsePosition(0));
Date d2 = f.parse(s2,new ParsePosition(0));
long msec = d2.getTime() - d1.getTime();
System.out.println("msec:"
Date d3 = new Date(msec );
System.out.println("date: " + d3);
String ss = f.format(d3);
System.out.println("ss:" + ss);
returns
17:05:49.931
instead of 01:05:49.931
even though msec returns correctly:
msec: 3949931
(a little bit more than an hour ofr those two points you specified).
Don't understand how it can be
at least with SimpleDateFormat
when you format it like that:
SimpleDateFormat f = new SimpleDateFormat("hh:mm:ss
Date d1 = f.parse(s1,new ParsePosition(0));
Date d2 = f.parse(s2,new ParsePosition(0));
long msec = d2.getTime() - d1.getTime();
System.out.println("msec:"
Date d3 = new Date(msec );
System.out.println("date: " + d3);
String ss = f.format(d3);
System.out.println("ss:" + ss);
returns
17:05:49.931
instead of 01:05:49.931
even though msec returns correctly:
msec: 3949931
(a little bit more than an hour ofr those two points you specified).
Don't understand how it can be
If you read the link I posted above it explains that you can only use DateFormat if the period is less than 24 hours.
Sorry yes - on the DateFormat, you'd need to do
df.setTimeZone(TimeZone.getTimeZone("UTC"));BUt DateFormat gives the same result.
I guess it is about Time Zone or somthing it is because Im in pAcificTome
String s1 = "10:35:22.189";
String s2 = "11:41:12.120";
DateFormat f = new SimpleDateFormat("HH:mm:ss
Date d1 = f.parse(s1,new ParsePosition(0));
Date d2 = f.parse(s2,new ParsePosition(0));
long msec = d2.getTime() - d1.getTime();
System.out.println("msec:"
Date d3 = new Date(msec );
System.out.println("date: " + d3);
String ss = f.format(d3);
System.out.println("ss:" + ss);
...so
f.setTimeZone(TimeZone.getTimeZone("UTC"));
String ss = f.format(d3);SOLUTION
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