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Combining =HYPERLINK() & =LOOKUP() in Excel

Posted on 2011-03-21
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Last Modified: 2012-05-11
Hello,

This is a follow-up question to two other threads which can be found here:

    1)  Determining the correct argument for =HYPERLINK() in Excel
    2)  Understanding the syntax in =HYPERLINK() in Excel

In the two files attached to this question:

    File1 has a some entries in col B under the heading "Num."  Col C has the heading "Link" but no data yet.
    File2\SheetA has entries in col E and col F under the headings "Num" and "Row" respectively

I have written a formula in File1 which works successfully to lookup data from File2\SheetA (it's off to the side in col F):

    =LOOKUP(B3,[File2.xlsx]SheetA!$E$2:$E$15,[File2.xlsx]SheetA!$F$2:$F$15)

in which:

    the lookup_value comes from File1:col B
    the lookup_vector is File2SheetA:col E
    the result_vector is  File2SheetA:col F

For simplicity, I will refer to this =LOOKUP() formula as L-Fxn.

Now, in File1:col C, under the heading "Link," I want to use =HYPERLINK() to create a column of links, for which the targets will be in File2\SheetB and have a cell reference in which the column is col A and the row is defined by L-Fxn.  In other words, for any value in File1:col B, I want to be able to click an adjacent link in col C and have it take me to the col A cell of a row in File2\SheetB defined by the data in File2\SheetB (cell reference = A&L-Fxn).

Example:

    File1:cell B3 value = 1629
        In File2\SheetB, the value 1629 is found in cell B4
        Cell C4 value = 604
    Therefore, the link in File1:cell C3
        should take me to File2\SheetB:cellA604

I've written plenty of =HYPERLINK() formulas in the past and I've tried several different changes to get it right but keep getting an error.  I think the tricky part is plugging in L-Fxn with the correct quotation marks, etc.  If someone could bail me out, I'd appreciate it.

Thanks
 File1.xlsm File2.xlsm
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Question by:Steve_Brady
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Accepted Solution

by:
Jignesh Thar earned 1000 total points
ID: 35189460
Steve - Try below in C3 of File1.xlsm.Sheet1. I tested and it works

=HYPERLINK(CONCATENATE("[File2.xlsm]SheetA!A",VLOOKUP(B3,[File2.xlsm]SheetA!$B:$C,2)),"Link")
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Assisted Solution

by:Arno Koster
Arno Koster earned 1000 total points
ID: 35189499
Usign cell functions, the lookup command can only return values from File2.xlsm that are adjecent to the search value. Therefor, you could add (in file2.xlsm) a column with numbers representing the row :


<b>    <c>   <d>
Num      Row      Position
1627      228      2
1628      596      3
1629      604      4
1630      612      5
1631      660      6
1632      636      7
1634      668      8
1635      676      9
1636      684      10
1638      692      11
1639      700      12
1641      732      13
1642      724      14
1643      740      15

The use the lookup function to return the position :

=LOOKUP(B3,[File2.xlsx]SheetA!$B$2:$B$15,[File2.xlsx]SheetA!$D$2:$D$15)
(this would return 4)

and use it to formulate the lookup function.

normally, the function

=HYPERLINK("[path\file2.xlsm]SheetA!C7"; "link")

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would generate a hyperlink with the text 'link' to cell C7.

=HYPERLINK("[path\file2.xlsm]SheetA!C" & C11; "link")

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would link to cell C5 in file2.xlsm when the value 5  is intered in cell C11 in file1.xlsm

but when using
=HYPERLINK("[path\file2.xlsm]SheetA!C" & LOOKUP(B3;'[path\File2.xlsm]SheetA'!$B$2:$B$15;'[path\File2.xlsm]SheetA'!$C$2:$C$15); "link")

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strangely this leads to a hyperlink that does not work

What does work however, is using the D column in file1 for this formula :
eg in D3
="[path\file2.xlsm]SheetA!C" &        LOOKUP(B3;'[path\File2.xlsm]SheetA'!$B$2:$B$15;'[path\File2.xlsm]SheetA'!$D$2:$D$15)

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and in C3 :
=HYPERLINK(D3; "link")

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Expert Comment

by:Arno Koster
ID: 35189527
I seem to have missed the way you want the hyperlink to work, forget the D column in file2 and use


LOOKUP(B3;'[path\File2.xlsm]SheetA'!$B$2:$B$15;'[path\File2.xlsm]SheetA'!$C$2:$C$15) as before...
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LVL 7

Expert Comment

by:Jignesh Thar
ID: 35189551
It worked for me if I use Concetenate function.
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Expert Comment

by:Arno Koster
ID: 35189738
jigneshthar,

i missed you comment while typing mine, sorry !
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Expert Comment

by:Jignesh Thar
ID: 35189773
No offense as this happens almost every other time with all of us :-)

Just wanted to highlight that I could see this working with single formula.
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Author Closing Comment

by:Steve_Brady
ID: 35420672
Thqanks!
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