Missing numbers found by query in MySQL, some complications

This is my database table ("table_number"):

id      Number      Name       Town
25          1           James       New York
57          1           Doris         Boston
78          2           Dave         Boston
89          7           Chuck        Boston
126        2           Bertie        New York
153        3           Marion       New York
198        5           Veronica    Boston
234        6           Allen          Boston

This is how I'd like it print
id      Number      Name      Town: Boston
                       
57          1           Doris         Boston
78          2           Dave         Boston
198        5           Veronica    Boston
234        6           Allen          Boston
89          7           Chuck        Boston

id      Number      Name      Town: New York

25          1           James       New York
126        2           Bertie        New York
153        3           Marion       New York

I got help from experts at EE with the code. I am not very fluent in SQL.
Since I have several identical Numbers, the code doesn't work correctly. It also seems like it is not possible to distinguish between Town = Boston and Town = New York. If I could do so, the problem is actually solved, I guess.
Please could someone of you Gurus help me?


SELECT MIN(rownum) min_Missing_Number 
  FROM (  SELECT id, 
                 Number, 
                 Name, 
                 Town,
                 @rownum := @rownum + 1 AS rownum 
            FROM table_number, 
                 (SELECT @rownum := 0) r 
        ORDER BY Number) t1 
 WHERE Number <> rownum AND Name = '$name' AND Town = '$town' AND id <=500;";

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Lennart EricsonAmateurAsked:
Who is Participating?
 
SharathData EngineerCommented:
There is no missing number for New York, Hence this query gives you Boston and missing number as 3.
SELECT Town, 
         MIN(RowNum) AS MissingNumber 
    FROM (  SELECT *, 
                   IF(@Town = Town,@rownum := @rownum + 1,@rownum := 1) AS RowNum, 
                   IF(@Town <> Town,@Town := Town,'ABC')                s 
              FROM Table_Number, 
                   (SELECT @rownum := 1, 
                           @Town := 'ABC') r 
          ORDER BY Town, 
                   Number) t1 
   WHERE Number <> RowNum 
GROUP BY Town;

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Here is the sample I tested.
SELECT * FROM Table_Number1 order by Town,Number;

+------+--------+----------+----------+
| id   | Number | Name     | Town     |
+------+--------+----------+----------+
|   57 |      1 | Doris    | Boston   |
|   78 |      2 | Dave     | Boston   |
|  198 |      5 | Veronica | Boston   |
|  234 |      6 | Allen    | Boston   |
|   89 |      7 | Chuck    | Boston   |
|   25 |      1 | James    | New York |
|  126 |      2 | Bertie   | New York |
|  153 |      3 | Marion   | New York |
+------+--------+----------+----------+
8 rows in set (0.00 sec)
SELECT Town, 
         MIN(RowNum) AS MissingNumber 
    FROM (  SELECT *, 
                   IF(@Town = Town,@rownum := @rownum + 1,@rownum := 1) AS RowNum, 
                   IF(@Town <> Town,@Town := Town,'ABC')                s 
              FROM Table_Number1, 
                   (SELECT @rownum := 1, 
                           @Town := 'ABC') r 
          ORDER BY Town, 
                   Number) t1 
   WHERE Number <> RowNum 
GROUP BY Town;
+--------+---------------+
| Town   | MissingNumber |
+--------+---------------+
| Boston |             3 |
+--------+---------------+
1 row in set (0.04 sec)

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0
 
SharathData EngineerCommented:
If you want the result as:
id      Number      Name      Town: Boston
                       
57          1           Doris         Boston
78          2           Dave         Boston
198        5           Veronica    Boston
234        6           Allen          Boston
89          7           Chuck        Boston

Then try this query.
SELECT t1.* 
  FROM table_number1 AS t1 
       JOIN (  SELECT Number, 
                      MAX(Id) AS ID 
                 FROM table_number
             GROUP BY Number) AS t2 
         ON t1.Number = t2.Number 
            AND t1.ID = t2.ID;

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0
 
SharathData EngineerCommented:
Typo in table name.
SELECT t1.* 
  FROM table_number AS t1 
       JOIN (  SELECT Number, 
                      MAX(Id) AS ID 
                 FROM table_number
             GROUP BY Number) AS t2 
         ON t1.Number = t2.Number 
            AND t1.ID = t2.ID;

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Lennart EricsonAmateurAuthor Commented:
Sharath_123,
You helped me out the other day and given the prerequisites I gave then, your solution was correct. In this question I have added Town. Town is an important variable since it separates the two Number series. I believe Town is a more important variable than is ID. Would you be kind enogh to consider it for a moment.
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Lennart EricsonAmateurAuthor Commented:
Sharath_123,

My question might not be as clear as it should have been. Let me add I want to find "the missing"number(s) in the Number series. After I have added Town to it, and I need to group or order by town, I don't know how to change the code you gave me the other day. That is a more clear statement and the question becomes How can I find the lowest missing number , if any, in each of the two series, the series for Boston and the series for New York?.
0
 
SharathData EngineerCommented:
ok, what is your expected result?
0
 
SharathData EngineerCommented:
Do you want the least missing number for each town?
0
 
Lennart EricsonAmateurAuthor Commented:
Yes. That's exactly what I want.
0
 
Lennart EricsonAmateurAuthor Commented:
You are my hero. Many thanks.
0
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