jquery to show hide div on mouse over

I have built a menu bar with divs and the drop down menus are divs as well. On mouse over on the mainmenu, I need the dropdown menu to be visible and on mouse out to be hidden. The drop down menu has table, anchors which the user can click on. I use jquery to showide the div. The problem I have is that after the dropdownmenu is visible and the mouse is inside the dropdowndiv, the dropdown gets hidden. I have attached the code below. Please advise as to how I can make the dropdown stay visible as long as the user is inside the dropdowndiv. Thanks

function DropMenu1MouseOver() 
	{
          $("#divDropMenu1").css('display', 'block');

        }

   function DropMenu1MouseOut()
        {
            $("#divDropMenu1").css('display', 'none');          
        }

  $(document).ready(function () {
            $('#divMainMenu1').bind('mouseover', DropMenu1MouseOver);
            $('#divMainMenu1').bind('mouseout', DropMenu1MouseOut);
});


 <div id="divMainNavigationContainer" runat="server">
                                <div id="divMainMenuContainer">
                                    <div id="divMainMenu1" class="MainMenus"  onclick="MainMenuClick(1)">
                                        Office Supplies
                                    </div>
				    //other mainmenu stuff
				</div>
 </div>

<div id="divDropMenu1" class="DropMenus">
//other stuff
<a href="something">somestuff</a>
</div>

Open in new window

TrialUser

Asked: 2011-03-22

Advertise Here

1 Solution

LVL 83

leakim971PluritechnicianCommented: 2011-03-22

Try to use .hover instead mouseover and mouseout : http://api.jquery.com/hover/

$('#divMainMenu1').hover(DropMenu1MouseOver,DropMenu1MouseOut);

Open in new window

TrialUserAuthor Commented: 2011-03-22

I am atually having to attach the events to both divMainMenu1 and to divDropMenu1 and so on. That is
because, when the mouse overs divdropmenu1, divmainmenu1's mouseout event fires. SO either of the following works. But it seems like a not so elegant way to do it since the same methods are
being called twice. Any thoughts on how this can be achieved?

//begin method 1
$('#divMainMenu1').hover(DropMenu1MouseOver, DropMenu1MouseOut);
$('#divDropMenu1').hover(DropMenu1MouseOver, DropMenu1MouseOut);gi
//end method1

//begin method 2

$('#divMainMenu1').bind('mouseover', DropMenu1MouseOver);
$('#divMainMenu1').bind('mouseout', DropMenu1MouseOut);
$('#divDropMenu1').bind('mouseover', DropMenu1MouseOver);
$('#divDropMenu1').bind('mouseout', DropMenu1MouseOut);
//end method 2