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check each letter and remove

Posted on 2011-03-23
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Last Modified: 2012-05-11
str1: "CLIO EXTREME TOM TOM (75)"
str2: "CLIO EXTREME TOMTOM (75)"

I would like to traverse each character in str1 if i find it in str2 remove that character from str2

if what remains is a space then that remains the only difference in the strings so flag it as false

this will allow me to ignore strings that have done this TOM TOM vs TOMTOM and by doing this character by character it doesnt matter if they rearranged the words.

I am working in vba

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Question by:PeterBaileyUk
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6 Comments
 
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Expert Comment

by:JezWalters
ID: 35196951
Wouldn't removing all spaces from both strings, and then comparing the strings give you the same result?
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Accepted Solution

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Scott McDaniel (Microsoft Access MVP - EE MVE ) earned 1000 total points
ID: 35196960
Have you looked into Soundex algorithms (i.e. "fuzzy matches") for these operations? Soundex algorithms can determine if one set of characters very closely mimics another, which is (basically) what you're trying to do.

http://allenbrowne.com/vba-Soundex.html
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Author Comment

by:PeterBaileyUk
ID: 35196964
botj interesting yes to Jez and i will look at the fuzzy logic
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Assisted Solution

by:JezWalters
JezWalters earned 1000 total points
ID: 35197003
You can remove spaces like this:
Option Explicit        ' Force explicit variable declaration
Option Compare Binary  ' Perform case-sensitive comparisons

Public Function RemoveSpace(pvarStrOption Explicit        ' Force explicit variable declaration
Option Compare Binary  ' Perform case-sensitive comparisons

Public Function RemoveSpace(pvarString As Variant) As String

    ' Declare variables
    Dim lngCharacter As Long

    ' Process string
    RemoveSpace = Nz(pvarString)  ' Cope with Null
    For lngCharacter = 1 To Len(RemoveSpace)
        If Mid(RemoveSpace, lngCharacter, 1) = " " Then
            RemoveSpace = Left(RemoveSpace, lngCharacter - 1) & Mid(RemoveSpace, lngCharacter + 1)
        End If
    Next

End Function

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Expert Comment

by:JezWalters
ID: 35197012
Once you've created this function, you can use it in a query like this:

SELECT *, RemoveSpace(YourField1) <> RemoveSpace(YourField2) As Different
FROM YourTable
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Expert Comment

by:JezWalters
ID: 35197052
How do you want to handle different capitalisation between the two strings?
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