c# windows app open another form on load

Hi,

I am building a windows app in which I need to do this.

1) when the user clicks the icon to lauch the app I want it to load the form but also load another form "window" that displays certain information from the DB. Its like automatic reminders.

Question is how do i get another form to launch when openeing the main form.

Please help

Thanks,

R8VI

R8VI

Asked: 2011-03-23

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1 Solution

LVL 52

Carl TawnSystems and Integration DeveloperCommented: 2011-03-23

You can simply have the Load event of the main form instantiate and show a secondary form:

// in load event of main form
SecondForm f = new SecondForm();
f.Show();

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LVL 3

MicMaticCommented: 2011-03-23

If you want to make sure your new form to stay on top of the other form, you might want to use .ShowDialog()

The code is almost the same as mentioned above:

FormReminders frmReminders = new FormReminders();
frmReminders.ShowDialog();

LVL 3

MicMaticCommented: 2011-03-23

My bad, I intended to use preview...

An example of a basic class:

public partial class frmMainForm : Form {
  public frmIudexnet() {
    InitializeComponent();

    //You call your second form here (asuming you already created you form with the IDE)
    FormName frm = new FormName();
    frm.ShowDialog();
  }

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R8VIAuthor Commented: 2011-03-23

Hi,

Sorry I should have been a bit more specfic, I want the second form (reminders) to load and be displayed top left for example but first form to be displayed in the middle on the screen and focus on the first form

Thanks for the help so far

Thanks,

R8VI

LVL 3

MicMaticCommented: 2011-03-23

In that case you should use this for your second form (after InitializeComponent()):

frmSecondForm.Show();

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You can set the position using your Form-properties in your IDE: StartPosition: manual. After that you can set your location property to 0; 0

after calling the new form you can use:

this.TopMost = true;

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that should keep your first form on top

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c# windows app open another form on load

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