Solved

PHP - Generate Checksum CRC-CCITT

Posted on 2011-03-23
1
1,271 Views
Last Modified: 2012-05-11
I apologize as I know very little about Hex but we have a GPS product that we need to send messages to (via UDP data posting) and I need to generate a 2 byte checksum value in PHP and don't know how to proceed.

The example says the following:

0x05d8 = CRC-CCITT (24 24 00 11 13 61 23 45 67 8f ff 50 00)

So, I need a PHP function where I can pass in that value in the parenthesis and get back the 05 D8 (I presume).

It very well may be that there is a PHP function already to do this.

Any help is greatly appreciated!

Thanks!!
0
Comment
Question by:khilles
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
1 Comment
 
LVL 5

Accepted Solution

by:
tsmgeek earned 500 total points
ID: 35203739
0

Featured Post

SharePoint Admin?

Enable Your Employees To Focus On The Core With Intuitive Onscreen Guidance That is With You At The Moment of Need.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Developers of all skill levels should learn to use current best practices when developing websites. However many developers, new and old, fall into the trap of using deprecated features because this is what so many tutorials and books tell them to u…
These days socially coordinated efforts have turned into a critical requirement for enterprises.
The viewer will learn how to count occurrences of each item in an array.
The viewer will learn how to create and use a small PHP class to apply a watermark to an image. This video shows the viewer the setup for the PHP watermark as well as important coding language. Continue to Part 2 to learn the core code used in creat…

734 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question