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excel macro to replace cells values and then get total unique values

Hi,

I need to write a macro that basically does the following -
for each row in the sheet, if the cell value in Column A exists within the cell value of Col D, then replace the Col D value with "".

I then need to get the unqiue number of values in Col D. Ive written the start of the macro but now im completely lost

any help would be great

cheers

test-macro
0
DiCanio13
Asked:
DiCanio13
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1 Solution
 
Curt LindstromCommented:
Maybe something like this?

try in attached file

Curt
Sub ReplaceCells_Click()
For i = 1 To 10
If Cells(i, 1) = Cells(i, 4) Then Cells(i, 4) = ""
Next i
Cells(i, 4) = Range("d1:d10").SpecialCells(xlCellTypeConstants).Count
End Sub

Open in new window

ReplaceCells.xls
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Curt LindstromCommented:
Or maybe like this if you want the total of the remaining values in column D

try in attached file

Curt
Sub ReplaceCells_Click()
    For i = 1 To 10
        If Cells(i, 1) = Cells(i, 4) Then Cells(i, 4) = ""
    Next i
    Cells(i, 4).Activate
    ActiveCell.FormulaR1C1 = "=SUM(R[-10]C:R[-1]C)"
End Sub

Open in new window

ReplaceCells-mod1.xls
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DiCanio13Author Commented:
Hi,

Instead of -
If Cells(i, 1) = Cells(i, 4) Then Cells(i, 4) = ""

i need If Cells(i,1) "exists in" Cells(i,4) then.....

If you understand?
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Curt LindstromCommented:
Do you have text in the cells? Like "Frog" in A1 and if  "GreenFrogJumps" in D1 you want "" in D1 but not if there is just "GreenJumps" in D1.

Curt
0
 
DiCanio13Author Commented:
Hey Curt,

Thats correct, if i have Col A as "test" and Col D has "testing" then i want col D to end up with "ing". I then wish to sum up all the unique values left in Col D. An example would be -

Col A Col B Col C Col D
test                       testing
frog                      green frog
test                       testing

would then look like this....
Col A Col B Col C Col D
test                        ing
frog                        green
test                         ing

....and the sum of unique values in Col D would be 2

Cheers
0
 
Curt LindstromCommented:
I've done the string manipulation. Is this how you want it to work?
I'm still looking at the unique counting solution

Try in attached file

Curt
Sub ReplaceCells_Click()

    Dim LeftPart As String
    Dim RightPart As String
    Dim StartPos As Long
Dim FoundLen As Long, DLen As Long
    For i = 1 To 10

        If InStr(1, Cells(i, 4), Cells(i, 1)) > 0 Then
            'Number of characters before found string
            StartPos = InStr(1, Cells(i, 4), Cells(i, 1)) - 1
            'Length of found string
            FoundLen = Len(Cells(i, 1))
            'Length of original string in column D
            DLen = Len(Cells(i, 4))
            'Characters to the left of found string
            LeftPart = Left(Cells(i, 4), StartPos)
            
            'Characters to the right of found string
            RightPart = Right(Cells(i, 4), DLen - StartPos - FoundLen)
            'Assembling the result
            Cells(i, 4) = LeftPart & RightPart
        End If
    Next i
End Sub

Open in new window

ReplaceCells-mod2.xls
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Curt LindstromCommented:
Are you using Excel 2007 or higher o does it have to work in Excel 2003?

Cheers,
Curt
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DiCanio13Author Commented:
no excel 2007 is perfect, the above code works brilliant! now we just need the sum of the unique values....
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Curt LindstromCommented:
Just to be sure of the definition of unique:
===========
would then look like this....
Col A Col B Col C Col D
test                        ing
frog                        green
test                         ing

....and the sum of unique values in Col D would be 2
=============
So in this case you mean to count "Green" and "ing" as the 2 unique values?

Cheers,
Curt
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DiCanio13Author Commented:
its cool, i can do the remainder using the filter -> Advanced option in excel

thanks for all your help with the initial problem
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Curt LindstromCommented:
Ok, that's what I was going to look into to build in an advance filter in the code. But if your happy with it as it is I'll stop looking at and we can close the question.

Cheers,
Curt
0
 
Curt LindstromCommented:
Ok, closed already :-) Thanks for grading and score!

Cheers,
Curt
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