PHP Regex question

Hello all,
 I'm having problem with php regex. What I want to do is;

$string = "[test-numberTest12-{anotherValue2}]some text here[/test]";

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I want my preg_match to match these values. -numberTest12- and {anotherValue2} should be case-insensitive, can contain numbers or letters anywhere (numbers and letters can be anywhere -beginning, end, middle...-)

What I try is a bit like BBCode but I'm not using them as BBCode, that's why I would like to make a underline here, this is not a BBCode but the logic is more or less the same.

I'm not good with regex but I tried;
preg_match("/\[test-([0-9]|[a-z])-\]/", $string)

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Doesn't work. I couldn't even get the first part done so I could jump to second value. I will be glad if anyone could help me out with this problem.
Who is Participating?
Beverley PortlockConnect With a Mentor Commented:
Try this code

$string = "[test-numberTest12-{anotherValue2}]some text here[/test]";

$pattern = '#.*\[test([^\{]+)\{(.+)\}\]#';

preg_match( $pattern, $string, $matches );

print_r( $matches );

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pixalaxAuthor Commented:
Hello bportlock;
 I have no idea what you wrote in $pattern but it works. If I might ask you to explain me a bit would it be too much?
Beverley PortlockCommented:
"I have no idea what you wrote in $pattern but it works"

:-D   That's regexes for you......

Let's look at the pattern '#.*\[test([^\{]+)\{(.+)\}\]#' and we will skip the delimiters so we start with


That splits up into the following logical sections

.*   \[test   ([^\{]+)   \{  (.+)  \}   \]

The first bit .* says 'there may be characters at the start

Next we have \[test and since [ is a normal regex character we need to escape it with a \ to indicate that it is DATA and not part of the regex controls. test is just the word 'test'. So this bit looks for data matching [test

Next we have ([^\{]+) which is a capture group (inside brackets) that is looking for any data that is NOT a curly brace and that data must occur at  least once (the plus sign)

Next we look for an opening brace \{

Next we look for at least one character (.+)

Next we look for a closing brace \}

and that's pretty much it
pixalaxAuthor Commented:
Wow, thank you very much. This is summing up lot's of things for me.

Before I had to use spaces in order to grab [xxx] now I realize with your help i don't need spaces at all, I can use .*\

(If I was using [xxx]text[/xxx][yyy]text[/yyy] it didn't work, I had to use spaces so my regex could grab them.

Thanks a billion for your fast reply and explanation.
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