Solved

Split hours worked between 2 times into shift buckets

Posted on 2011-03-24
3
640 Views
Last Modified: 2012-08-13
I have a table of clock in times and clock out times which I need to separate into 3 shift buckets using sql 2000,  based on hours worked durring the shift. The shifts go from Midnight to 7AM (Third Shift), 7AM to 3PM (First Shift), and 3PM to Midnight (Second Shift). The shifts overlap so I need to know labor hours worked in each shift.
Here is an data example.

EmployeeName ClockIN ClockOut
Joe                     4:30AM 2:00PM
John                   1:00AM 8:00AM
Steve                  2:00PM 10:00PM

And the results would look like this

EmployeeName ThirdShift FirstShift SecondShift
Joe                         2.5           7                  0
John                        6              1                 0
Steve                       0              1                 7
0
Comment
Question by:fdorazio
  • 2
3 Comments
 
LVL 23

Accepted Solution

by:
wdosanjos earned 450 total points
ID: 35211370
Please try the following:

create table #shifts (sname varchar(20), ShiftStart datetime, ShiftEnd datetime)
insert into #shifts values('T', '12:00AM','07:00AM')
insert into #shifts values('F', '07:00AM','03:00PM')
insert into #shifts values('S', '03:00PM',DATEADD(day,1,'12:00AM'))

select EmployeeName,
       CAST(ClockIn as datetime) ClockIn,
       CAST(ClockOut as datetime) ClockOut
  into #temp
  from YourHoursWorkedTable
  
update #temp
       set ClockOut = DATEADD(day,1,ClockOut)
  where ClockOut < ClockIn

Select 
    EmployeeName, 
	SUM(case when sname = 'T' then HW else 0 end) ThirdShift,
	SUM(case when sname = 'F' then HW else 0 end) FirstShift,
	SUM(case when sname = 'S' then HW else 0 end) SecondShift
  from
	(
		select e.EmployeeName, s.sname, 
			DATEDIFF(
				minute,
				case when e.ClockIn > s.ShiftStart then e.ClockIn else s.ShiftStart end,
				case when e.ClockOut < s.ShiftEnd then e.ClockOut else s.ShiftEnd end) / 60.0 HW
		 from #temp e 
		 inner join #shifts s on s.ShiftStart between e.ClockIn and e.ClockOut 
							  or s.ShiftEnd between e.ClockIn and e.ClockOut
	) hrs
Group By EmployeeName
Order By EmployeeName

drop table #temp
drop table #shifts

Open in new window

0
 

Author Comment

by:fdorazio
ID: 35236406
The third shift actually starts on the day before from 11:00PM to 7:00AM. Instead of Midnight to 7:00AM. Is there a way to account for that?
0
 
LVL 23

Expert Comment

by:wdosanjos
ID: 35243875
Does the third shift overlaps with the second?  Like this:

First:       7:00 AM -   3:00 PM
Second:  3:00 PM -   midnight
Third:    11:00 PM  -  7:00 AM

In that case if someone worked from 11:00 PM - 7:00 AM, how it should show on the report?

EmployeeName ClockIN    ClockOut
Joe                     11:00PM 7:00AM

EmployeeName ThirdShift FirstShift SecondShift
Joe                         8           0                  1

Anyway, the code below returns the results above:
create table #shifts (sname varchar(20), ShiftStart datetime, ShiftEnd datetime)
insert into #shifts values('T', '11:00PM',DATEADD(day,1,'07:00AM'))
insert into #shifts values('T', '12:00AM','07:00AM')
insert into #shifts values('F', '07:00AM','03:00PM')
insert into #shifts values('S', '03:00PM',DATEADD(day,1,'12:00AM'))

select EmployeeName,
       CAST(ClockIn as datetime) ClockIn,
       CAST(ClockOut as datetime) ClockOut
  into #temp
  from YourHoursWorkedTable
  
update #temp
       set ClockOut = DATEADD(day,1,ClockOut)
  where ClockOut < ClockIn

Select 
    EmployeeName, 
	SUM(case when sname = 'T' then HW else 0 end) ThirdShift,
	SUM(case when sname = 'F' then HW else 0 end) FirstShift,
	SUM(case when sname = 'S' then HW else 0 end) SecondShift
  from
	(
		select e.EmployeeName, s.sname, 
			DATEDIFF(
				minute,
				case when e.ClockIn > s.ShiftStart then e.ClockIn else s.ShiftStart end,
				case when e.ClockOut < s.ShiftEnd then e.ClockOut else s.ShiftEnd end) / 60.0 HW
		 from #temp e 
		 inner join #shifts s on s.ShiftStart between e.ClockIn and e.ClockOut 
							  or s.ShiftEnd between e.ClockIn and e.ClockOut
	) hrs
Group By EmployeeName
Order By EmployeeName

drop table #temp
drop table #shifts

Open in new window

0

Featured Post

What is SQL Server and how does it work?

The purpose of this paper is to provide you background on SQL Server. It’s your self-study guide for learning fundamentals. It includes both the history of SQL and its technical basics. Concepts and definitions will form the solid foundation of your future DBA expertise.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Let's review the features of new SQL Server 2012 (Denali CTP3). It listed as below: PERCENT_RANK(): PERCENT_RANK() function will returns the percentage value of rank of the values among its group. PERCENT_RANK() function value always in be…
Everyone has problem when going to load data into Data warehouse (EDW). They all need to confirm that data quality is good but they don't no how to proceed. Microsoft has provided new task within SSIS 2008 called "Data Profiler Task". It solve th…
Via a live example, show how to backup a database, simulate a failure backup the tail of the database transaction log and perform the restore.
Viewers will learn how to use the SELECT statement in SQL and will be exposed to the many uses the SELECT statement has.

786 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question