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2 children , 2 jobs with execv

a parent process creates 2 children.
child1: ls
child2: ask for 2 numbers, and add them
but output is not what I really expect...

#include<stdio.h>
#include<unistd.h>
#include<stdlib.h>

int main()
{
int pid1, pid2;
char* args[] = {"/bin/ls",(char*)0};
      p1=fork();
      if(p1!=0){
                printf("\n parent");
                wait(0);
      }
      else{//1st child
                 p2=fork();
                 if(p2!=0){//1st child
                           printf("\n result of ls is..\n ");
                           execv("/bin/ls",args);
                           wait(0);
                           exit(0);
                           }

                 else{//2nd child
                     printf("\n give 2 ints separ. with space \n");
                     scanf("%d  %d",&a,&b);
                     c=a+b;
                     printf("\n summ of the 2 numbers is: %d\n",c);
                     exit(0);
                 }//end 2nd child
      }//end 1st child
      return 0;
}//end main

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ozo

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dimi67

ASKER

what do you mean "/bin/ls is closing stdin"? It means I cannot read from keyboard?
And why dup it?

ozo

o The child process has its own copy of the parent's descriptors.
These descriptors reference the same underlying objects, so
that, for instance, file pointers in file objects are shared
between the child and the parent, so that an lseek(2) on a
descriptor in the child process can affect a subsequent read or
write by the parent.