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how to mark a certain line in a multiline data record?

Posted on 2011-03-25
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Last Modified: 2012-05-11
I need to mark the start of a line with a # sign following the above line with the name of the Operating System in a multiline data record.

For example,

__Data__
@test_scsi  
(memory test)
windows (xp)
#dklldkdslsjkflskfljsklfjklsjfklsjkflsjklfs


What I don't want is to put a #sign on any lines if a line contains any number lines following the above line of the Operating System.

For example, this data record contains a number line so no # sign is needed.

__Data__
@test_scsi  
(memory test)
windows (xp)
1. dklldkdslsjkflskfljsklfjklsjfklsjkflsjklfs
djkfkdljkfldsjkfljsklfjls

The problem with my code below is that it puts a # sign even if the line following the Operating line contains a number line.

For example, the code below puts a #sign even when the data record contains a number line

__Data__
@test_scsi  
(memory test)
windows (xp)
1. dklldkdslsjkflskfljsklfjklsjfklsjkflsjklfs
#fkkfkfkfkfkfkf

#!/usr/bin/perl

use strict;
use warnings;

$/='__Data__';

my $os = '(?:windows|linux|mac)';
open 'FH','<',"/home/data_record";

while (<FH>)
{
          $_ =~ s/(^\@[^\n]*)(.*?)(^$os[^\n]*)(.*?)(^[a-zA-Z][^\n]*$)(.*?)/$1$2$3$4#$5$6/ms;
            print;
}
0
Comment
Question by:areyouready344
  • 2
4 Comments
 
LVL 4

Expert Comment

by:dagesi
ID: 35216172
Within the grouping for $5, have you tried adding a (^\d) - the intent to say that it isn't starting with a number?
0
 
LVL 4

Expert Comment

by:dagesi
ID: 35216195
Or I guess that would actually be \D , wouldn't it?
0
 
LVL 26

Accepted Solution

by:
wilcoxon earned 500 total points
ID: 35216260
This should do it...
#!/usr/bin/perl

use strict;
use warnings;

$/='__Data__';

my $os = '(?:windows|linux|mac)';
open FH, '<', '/home/data_record' or die "could not open data_record: $!";

while (<FH>) {
    s{^(\@.*\n$os[^\n]+\n)(?!\d)}{$1#}ms;
    print;
}

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Author Comment

by:areyouready344
ID: 35216452
Thanks Wilcoxon, I can not find no problems with your code. In other words, its working solid.
0

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