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Use one line command to run compress directoies

Posted on 2011-03-25
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Last Modified: 2012-05-11
Hi, I have an application to compress each directory. There are 20 directoies.
TarApp 1
TarApp 2
TarApp 3
...
TarApp 20

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Of course we can use a loop in a batch file.
#!/bin/bash
for (( i=1; i<21; i++ ))
do
	TarApp $i
done

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Now I just want one line command to accomplish it.
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Question by:zhshqzyc
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8 Comments
 
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Expert Comment

by:simon3270
ID: 35216479
I suppose that you don't mean:
for (( i=1; i<21; i++ )); do TarApp $i; done

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If TarApp is a shell script, then you could modify that to accept multiple arguments.  If it is the "tar" command, then it already accepts mutlitple arguments.  In either case, you can then say:
TarApp 1 2 3 4 5 6 7 8 9 010 11 12 13 14 15 16 17 18 19 20

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Expert Comment

by:pilson66
ID: 35216537
for t in $(find /home/ -type d -mindepth 1 -maxdepth 1); do tar -czf /path/to/archives/${t}.tar.gz ${t}/; done

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Expert Comment

by:pilson66
ID: 35216551

for t in $(find /home/ -type d -mindepth 1 -maxdepth 1); do TarApp ${t}/; done

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Expert Comment

by:pilson66
ID: 35216563
for t in $(seq 1 20); do TarApp ${t}; done
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Author Comment

by:zhshqzyc
ID: 35216575
TarApp is a batch file.
#!/bin/bash
tar cvzf $1.tgz $1

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Expert Comment

by:pilson66
ID: 35216600
You need to get dirnames from command line?
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Expert Comment

by:simon3270
ID: 35216661
Just change the script to

#!/bin/bash
for name in $*
do
  tar cvzf ${name}.tgz $name
done

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Accepted Solution

by:
simon3270 earned 200 total points
ID: 35216665
Then call it as:
    TarApp 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
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