MaxDes101
asked on
initial velocity
if a person shoots a basketball overhand from a position 8 feet above the floor then the path can sometimes be modeled by the quadratic function defined by
f(x)= -16x^2/0.434v^2+1.15x+8
where v is the initial velocity of the ball in feet per second...so if the hoop is 10 feet high and 15 feet away what initial velocity does the basketball have?
- So I did what the online homework said to do and subed 15 for x and put it in the graphing calc and then put y= 10 in the graph calc and found the intersect...which is 0.044 but I can not for the life of me get the velocity
Totally feel like I am missing something critical.
Any help is appreciated.
f(x)= -16x^2/0.434v^2+1.15x+8
where v is the initial velocity of the ball in feet per second...so if the hoop is 10 feet high and 15 feet away what initial velocity does the basketball have?
- So I did what the online homework said to do and subed 15 for x and put it in the graphing calc and then put y= 10 in the graph calc and found the intersect...which is 0.044 but I can not for the life of me get the velocity
Totally feel like I am missing something critical.
Any help is appreciated.
Removed "Computer Servers" from the Zones.
rindi,
EE ZA Storage
charlestasse
You need to replace your hard drive
>> y = f(x)= -16 x²/0.434v² + 1.15x + 8
Any idea where this formula comes from? I didn't try to derive the formula, but I'll accept it as a given, since I gather it is part of the problem. I guess buried in it are things like the angle at which the shooter throws the ball.
Did you miss a set of parenthesis. Do you think the formula is actually:
>> y = f(x)= -16 x²/(0.434v²) + 1.15x + 8
>> I did what the online homework said to do and subed 15 for x ... put y= 10
So, is this what you did?
10 = -16 (15)²/(0.434v²) + 1.15(15) + 8
All I see here are numbers and v² which is solvable.
Any idea where this formula comes from? I didn't try to derive the formula, but I'll accept it as a given, since I gather it is part of the problem. I guess buried in it are things like the angle at which the shooter throws the ball.
Did you miss a set of parenthesis. Do you think the formula is actually:
>> y = f(x)= -16 x²/(0.434v²) + 1.15x + 8
>> I did what the online homework said to do and subed 15 for x ... put y= 10
So, is this what you did?
10 = -16 (15)²/(0.434v²) + 1.15(15) + 8
All I see here are numbers and v² which is solvable.
Your equation is a mess
but given that there maybe dimensions hidden in the constants and the it is a very special equation ,note that at x = 15 f(x) should be 10 because the ball should be at the height of the basket. putting x = 15 and f(x) = 10 the only unknown in your equation is v. solve for v.
but given that there maybe dimensions hidden in the constants and the it is a very special equation ,note that at x = 15 f(x) should be 10 because the ball should be at the height of the basket. putting x = 15 and f(x) = 10 the only unknown in your equation is v. solve for v.
>> putting x = 15 and f(x) = 10 the only unknown in your equation is v. solve for v.
I thought I did that:
>> 10 = -16 (15)²/(0.434v²) + 1.15(15) + 8
I thought I did that:
>> 10 = -16 (15)²/(0.434v²) + 1.15(15) + 8
"I thought I did that"
indeed you did
indeed you did
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